An alternating source drives a series RLC circuit with an emf amplitude of 6.05 V, at a phase angle of +30.3°. When the potential difference across the capacitor reaches its maximum positive value of +5.32 V, what is the potential difference across the inductor (sign included)?

University Physics Volume 2
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ISBN:9781938168161
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Chapter15: Alternating-current Circuits
Section: Chapter Questions
Problem 3CQ: In an RLC series circuit, can the voltage measured across the capacitor be greater than the voltage...
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An alternating source drives a series RLC circuit with an emf amplitude of 6.05 V, at a phase angle of +30.3°. When the potential difference across the capacitor reaches its maximum positive value of +5.32 V, what is the potential difference across the inductor (sign included)?

Expert Solution
Step 1

Given data

*The emf amplitude is Em = 6.05 V

*The phase angle is φ=30.30

*The potential difference across the capacitor reaches its maximum positive value is Vc=5.32 V

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