An applied force of 14.4 N acts on a 2.50 kg mass that is initiallyt at rest. over a distance 2.09 m the object changes its kinetic energy by 19.3 j. what is the coefficient of kinetic friction?

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Chapter7: Energy Of A System
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Problem 7.8CQ: If only one external force acts on a particle, does it necessarily change the particles (a) kinetic...
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An applied force of 14.4 N acts on a 2.50 kg mass that is initiallyt at rest. over a distance 2.09 m the object changes its kinetic energy by 19.3 j. what is the coefficient of kinetic friction?

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Step 1

Given , Applied Force (F) = 14.4 N

           mass (m) = 2.5 kg

          initial velocity = 0 

         distance (s) = 2.09 m

       Change in Kinetic Energy KE = 19.3 J

 

Some portion of work done by the force is converted in to kinetic energy of the object and some potion of it is lost in overcoming the friction. 

 

Work done by the force = (change in K.E ) + (energy lost in friction )

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