An aqueous solution containing 5.41 g of lead(II) nitrate is added to an aqueous solution containing 7.20 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. balanced chemical equation: Pb(NO,),(aq) + 2KCI(aq) → P6C1L, (s) + 2KNO,(aq) What is the limiting reactant? O potassium chloride lead(II) nitrate The percent yield for the reaction is 89.0%. How many grams of the precipitate are formed? precipitate formed: 4.04 How many grams of the excess reactant remain? excess reactant remaining: 9.39

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Chapter3: Calculations With Chemical Formulas And Equaitons
Section: Chapter Questions
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An aqueous solution containing 5.41 g of lead(II) nitrate is added to an aqueous solution containing 7.20 g of
potassium chloride.
Enter the balanced chemical equation for this reaction. Be sure to include all physical states.
balanced chemical equation: Pb(NO,),(aq) + 2KCI(aq) → P6C1L, (s) + 2KNO,(aq)
What is the limiting reactant?
O potassium chloride
lead(II) nitrate
The percent yield for the reaction is 89.0%. How many grams of the precipitate are formed?
precipitate formed: 4.04
How many grams of the excess reactant remain?
excess reactant remaining: 9.39
Transcribed Image Text:An aqueous solution containing 5.41 g of lead(II) nitrate is added to an aqueous solution containing 7.20 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. balanced chemical equation: Pb(NO,),(aq) + 2KCI(aq) → P6C1L, (s) + 2KNO,(aq) What is the limiting reactant? O potassium chloride lead(II) nitrate The percent yield for the reaction is 89.0%. How many grams of the precipitate are formed? precipitate formed: 4.04 How many grams of the excess reactant remain? excess reactant remaining: 9.39
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