The reaction between aluminum and iron(III) oxide can generate temperatures approaching 3000°C and is used in welding metals: 2Al + Fe,03 → Al,O3 +2Fe In one process, 123 g of Al are reacted with 601 g of Fe,03. Calculate the mass (in grams) of Al,O3 formed, and determine the amount of excess reagent left at the end of the reaction. mass of Al,O3 formed: amount of excess reagent left:

The reaction between aluminum and iron(III) oxide can generate temperatures approaching 3000°C and is used in welding metals: 2Al + Fe,03 → Al,O3 +2Fe In one process, 123 g of Al are reacted with 601 g of Fe,03. Calculate the mass (in grams) of Al,O3 formed, and determine the amount of excess reagent left at the end of the reaction. mass of Al,O3 formed: amount of excess reagent left:

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter9: Chemical Quantities

Section: Chapter Questions

Problem 12CR: What is meant by a limiting reactant in a particular reaction? In what way is the reaction...

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Consider the equation: 2A+B5C. If 10.0 g of A reacts with 5.00 g of B. how is the limiting reactant determined? Choose the best answer and explain. l type='a'> Choose the reactant with the smallest coefficient in the balanced chemical equation. So in this case, the limiting reactant is B. Choose the reactant with the smallest mass given. So in this case, the limiting reactant is The mass of each reactant must be converted to moles and then compared to the ratios in the balanced chemical equation. So in this case, the limiting reactant cannot be determined without the molar masses of A and B. The mass of each reactant must he converted to moles first. The reactant with the fewest moles present is the limiting reactant. So in this case, the limiting reactant cannot be determined without the molar masses of A and B. The mass of each reactant must be divided by their coefficients in the balanced chemical equation, and the smallest number present is the limiting reactant. So in this case, there is no limiting reactant because A and B arc used up perfectly.
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