An aqueous solution containing glucose has a vapor pressure of 18.6 torr at 25°C. What would be the vapor pressure of this solution at 45°C? Thevapor pressure of pure water is 23.8 torr at 25 °C and 71.9 torr at 45°C.Vapor pressureIf the glucose in the solution were substituted with an equivalent amount (moles) of NaCl, what would be the vapor pressure at 45°C?Vapor pressuretorrtorrSubmit AnswerTry Another Version5 item attempts remaining

Question
Asked Jan 30, 2019
166 views
An aqueous solution containing glucose has a vapor pressure of 18.6 torr at 25°C. What would be the vapor pressure of this solution at 45°C? The
vapor pressure of pure water is 23.8 torr at 25 °C and 71.9 torr at 45°C.
Vapor pressure
If the glucose in the solution were substituted with an equivalent amount (moles) of NaCl, what would be the vapor pressure at 45°C?
Vapor pressure
torr
torr
Submit Answer
Try Another Version
5 item attempts remaining
help_outline

Image Transcriptionclose

An aqueous solution containing glucose has a vapor pressure of 18.6 torr at 25°C. What would be the vapor pressure of this solution at 45°C? The vapor pressure of pure water is 23.8 torr at 25 °C and 71.9 torr at 45°C. Vapor pressure If the glucose in the solution were substituted with an equivalent amount (moles) of NaCl, what would be the vapor pressure at 45°C? Vapor pressure torr torr Submit Answer Try Another Version 5 item attempts remaining

fullscreen
check_circle

Expert Answer

Step 1

Let P0 be the vapor pressure of the pure solvent and p be the vapor pressure of solution.

i be the van't Hoff factor

x be the mole fraction of the solute.

The expression for relative lowering of pressure is:

 

fullscreen
Step 2

At 250C, for a solution of glucose in water, 

P0=23.8 torr

p=18.6 torr

Since glucose does not dissociate or associate in water, so i=1

Substituting the values to get mole fraction of glucose :

fullscreen
Step 3

At 450C for a solution of glu...

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Science

Chemistry

Solutions

Related Chemistry Q&A

Find answers to questions asked by student like you

Show more Q&A add
question_answer

Q: The reaction rate of the following reaction:aA +bB ==> cC is known to be:k[A] 0 [B]2 Now answer t...

A: Rate of reaction and concentration of reactants are related as per rate law.Each reactant concentrat...

question_answer

Q: 0.3043 g of pure KHP was weighed out and titrated to an end point with 15.12 mL of a NaOH solution t...

A: Neutralization reaction between KHP (C8H5KO4) and NaOH is given below,

question_answer

Q: Why CH3CH2OH is most soluble is water?

A: Because of hydrogen atom in ethanol is directly bonded to oxygen atom, which can form hydrogen bondi...

question_answer

Q: Átom?

A:  Step 1:The entire universe is composed of energy and matter. Anything around us that has holds mass...

question_answer

Q: Which of the following statements best describes the role of neutrons in the nucleus? The neutrons s...

A: The atom is smallest particle of any element that exists. The atom itself is composed of three sub-p...

question_answer

Q: Please Write out the Mechanism of the reachon betuween Custeine hudrochloride and acetone to form th...

A: Acetone with cysteine hydrochloride gives the corresponding product.

question_answer

Q: 4. Which molecule is polar? a. C2H4 b. CS2 c. CH6 d. SO2 e. CF4

A: If a molecule has a dipole moment, it is termed as a polar molecule. Symmetrical molecules are non-p...

question_answer

Q: ) Complete Question#9 1 CCl Heat + CH3CC 2- CH2 1. 03 2.Zn/H30+ CH3

A: Fridel-crafts acylation:

question_answer

Q: For the reactionCH4(g) + 2O2(g)CO2(g) + 2H2O(g)H° = -802.3 kJ and S° = -5.2 J/KThe maximum amount of...

A: Given : Change in enthalpy is -802.3 kJ, change in entropy is -5.2 J/K, temperature is 259 K and pre...