An archer shoots an 18.0-gram arrow at a 43.0-gram target on a wall 32.0 m high. If the arrow is shot at a velocity of v0 = 60.0 m/s, the speed of the arrow is 54.5 m/s when it reaches the target. If the arrow becomes embedded in the target and they both fly off the wall together, at what speed will they leave the wall? Should I use 60.0 m/s in the equation or 54.5 m/s: V’=(0.018)(60.0m/s)/ (0.061)  -or-  V’=(0.018)(54.5m/s)/ (0.061)

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