How to solve? Question 3 of 15An astronomical telescope (magnification = 120) is adjusted for a relaxed eye (output rays areparallel to each other) when the two lenses are 1.20 m apart.What is the focal length of each lens?Hint : Take the absolute value for the magnificationO A) fobjective = 1.195 mfeyepiece = 5.0 mmB) fobjective = 1.190 mfeyepiece = 10.0 mmO C) fobjective = 1.185 mfeyepice = 15.0 mmO D) fobjective = 1.180 mfeyepice = 20.0 mmO E) fobjectivefeyepice= 1.170 m= 30.0 mm

Magnification of telescope in normal adjustment = f₀/fe

Answered: An astronomical telescope…

An astronomical telescope (magnification = 120) is adjusted for a relaxed eye (output rays are parallel to each other) when the two lenses are 1.20 m apart. What is the focal length of each lens?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter26: Image Formation By Mirrors And Lenses

Section: Chapter Questions

Problem 40P

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