Momo with mass m is sliding down an inclined plane that makes an angle o relative to the horizontal. The coefficient of kinetic friction between Momo and the inclined plane is Pk. Obtain an expressionfor Momo's acceleration along the incline.Assign a rotated Cartesian plane so that the acceleration is along the positive x-axis and the normal force is along the positive y-axis.The component of the weight parallel to Momo's acceleration is Wx = mgThe magnitude of the frictional force is f = PkThe normal force on Momo is n- mgWith these expressions and applying Newton's second law, we arrivean expression for Momo's acceleration:a =- Pk An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vA. Piece B with mass mg travels to the right with speed vg. Show thevelocity of piece B in tems of ma, mB and VA-Solution:Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:PBf + PAf =0Substituting the expression for momentum results tomgvmAV= 0Deriving the expression for the velocity of piece B results toV=(ma/mNA

Answered: Image /qna-images/answer/16c5399c-340d-4953-8a2c-e8081308fcb0.jpg

An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vA. Piece B with mass mg travels to the right with speed vg. Show the velocity of piece B in tems of ma, mB and VA- Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf =0 Substituting the expression for momentum results to mgv mAV = 0 Deriving the expression for the velocity of piece B results to =(ma/m VA

An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vA. Piece B with mass mg travels to the right with speed vg. Show the velocity of piece B in tems of ma, mB and VA- Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf =0 Substituting the expression for momentum results to mgv mAV = 0 Deriving the expression for the velocity of piece B results to =(ma/m VA

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: More Applications Of Newton’s Laws

Section: Chapter Questions

Problem 64P: If a single constant force acts on an object that moves on a straight line, the objects velocity is...

See similar textbooks

Similar questions

If a single constant force acts on an object that moves on a straight line, the objects velocity is a linear function of time. The equation v = vi + at gives its velocity v as a function of time, where a is its constant acceleration. What if velocity is instead a linear function of position? Assume that as a particular object moves through a resistive medium, its speed decreases as described by the equation v = vi kx, where k is a constant coefficient and x is the position of the object. Find the law describing the total force acting on this object.
If the vector components of the position of a particle moving in the xy plane as a function of time are x(t)=(2.5ms2)t2i and y(t)=(5.0ms3)t3j, when is the angle between the net force on the particle and the x axis equal to 45?
A block is being pulled by a rope up the surface of an inclined plane at constant velocity. Which of the following is true of the tension in the rope T, the force due to friction Ff, and the component of the block’s weight parallel to the plane wp?
the coefficient of static friction between block A and a horizontal floor is 0.320, and the coefficient of static friction between block B and the floor is 0.300. The mass of each block is 2.00kg,and they are connected together by a cord. If a horizontal force F pulling on block B is slowly increased ,in a direction parallel to the connectin cord,until the block start sliding ,what is the magnitude of F at the instant that they start to slide?
s shown, the mass of block 1 is m1 = 4.0 kg and the mass ofblock 2 is m2 = 8.0 kg. Block 1 sits on an incline with an angle of37º. The coefficient of kinetic friction between m1 and the inclinedsurface is μk = 0.40. (a) What is the minimum coefficient of staticfriction if the system is to remain at rest? b) Assuming that μs isless than this value, what is the acceleration of the system?
A mass with a m mass is being pulled along a horizontal rope with a constant tension T at angle theta above the horizontal. If the coefficent of kinetic friction is μk, what is the acceleration a of the mass?
f the mass of the box is 2.55 kg, the angle of the incline is 40o, and the coefficient of static friction, , between the crate and the incline is 0.37, rank the forces according to their magnitudes. Prompt 1The weight of the block Answer for prompt 1 The weight of the block Prompt 2The Static Friction Force between the block and the ramp Answer for prompt 2 The Static Friction Force between the block and the ramp Prompt 3The Normal Force between the block and the ramp Answer for prompt 3 The Normal Force between the block and the ramp Prompt 4The Tension in the string
If the 1 kg standard body has an acceleration of 2.00 m/s2 at 20.0 to the positive direction of an x axis, what are (a) the x component and (b) the y component of the net force acting on the body, and (c) what is the net force in unit-vector notation?
A body of mass m moves in a horizontal direction such that at time t its position is given by xt) = a cos(wt + ) where a, w, and are constants. What is the time dependent force acting on the body?
a block of mass m 5.00 kg ispulled along a horizontal frictionless floor by a cordthat exerts a force of magnitude F = 12.0 N at anangle u = 25.0. (a) What is the magnitude of theblock’s acceleration? (b) The force magnitude F isslowly increased. What is its value just before theblock is lifted (completely) off the floor? (c) What isthe magnitude of the block’s acceleration just before it is lifted(completely) off the floor?
A block with a mass of m = 46 kg rests on a frictionless surface and is subject to two forces acting on it. The first force is directed in the negative x-direction with a magnitude of F1 = 10.5 N. The second has a magnitude of F2 = 23.5 N and acts on the body at an angle θ = 23° measured from horizontal, as shown. a) Write an expression for the component of net force, Fnet,x, in the x-direction, in terms of the variables given in the problem statement. b)Write an expression for the magnitude of the normal force, FN, acting on the block, in terms of F2 and the other variables of the problem. Assume that the surface it rests on is rigid. c)Find the block's acceleration in the x-direction, ax, in meters per second squared.
A block with a mass of m = 46 kg rests on a frictionless surface and is subject to two forces acting on it. The first force is directed in the negative x-direction with a magnitude of F1 = 10.5 N. The second has a magnitude of F2 = 23.5 N and acts on the body at an angle θ = 23° measured from horizontal, as shown. a)Write an expression for the component of net force, Fnet,x, in the x-direction, in terms of the variables given in the problem statement. b)Write an expression for the magnitude of the normal force, FN, acting on the block, in terms of F2 and the other variables of the problem. Assume that the surface it rests on is rigid.