An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of VA. Piece B with mass mg travels to the right with speed vg. Show the velocity of piece B in terms of mA, mg and VA: Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf =0 Substituting the expression for momentum results to mgV mAV = 0 Deriving the expression for the velocity of piece B results to V =(mA/m VA
An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of VA. Piece B with mass mg travels to the right with speed vg. Show the velocity of piece B in terms of mA, mg and VA: Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf =0 Substituting the expression for momentum results to mgV mAV = 0 Deriving the expression for the velocity of piece B results to V =(mA/m VA
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter8: Momentum And Collisions
Section: Chapter Questions
Problem 13OQ
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