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An automobile of mass M=5400 kg is moving at a speed of 30 m/s The engine is disengaged suddenly at t= 0 sec. Assume that the equation of motion after t=0 is given by dv 5400 v dx -8.276 v2 – 2000 Where v= v(t) is the speed (m/sec) of the car at t. The left side represents Mv (dv/dx).The first term on the right side is the aerodynamics drag, I|||||| II||\|and the second term is the rolling resistance of the tires. Calculate how far the car travels until the speed reduces to 15 m/sec.(hint: the equation of motion may be integrated as 30 5400 v dv E dx = x 15 8.276 v2+2000 Evaluate the preceding equation using Simpson rule).

An automobile of mass M=5400 kg is moving at a speed of 30 m/s The engine is disengaged suddenly at t= 0 sec. Assume that the equation of motion after t=0 is given by dv 5400 v dx -8.276 v2 – 2000 Where v= v(t) is the speed (m/sec) of the car at t. The left side represents Mv (dv/dx).The first term on the right side is the aerodynamics drag, I|||||| II||\|and the second term is the rolling resistance of the tires. Calculate how far the car travels until the speed reduces to 15 m/sec.(hint: the equation of motion may be integrated as 30 5400 v dv E dx = x 15 8.276 v2+2000 Evaluate the preceding equation using Simpson rule).

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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1. An automobile of mass M=5400 kg is moving at a speed of 30 m/ş The engine is disengaged suddenly at t= 0 sec. Assume that the equation of motion after t=0 is given by dv 5400 v dx -8.276 v? – 2000 Where v= v(t) is the speed (m/sec) of the car at t. The left side represents Mv (dv/dx).The first term on the right side is the aerodynamics drag, \\\\\||\ ||\and the second term is the rolling resistance of the tires. Calculate how far the car travels until the speed reduces to 15 m/sec.(hint: the equation of motion may be integrated as -30 5400 v dv =E dx = x 8.276 v2+2000 Evaluate the preceding equation using Simpson rule).
Transcribed Image Text:1. An automobile of mass M=5400 kg is moving at a speed of 30 m/ş The engine is disengaged suddenly at t= 0 sec. Assume that the equation of motion after t=0 is given by dv 5400 v dx -8.276 v? – 2000 Where v= v(t) is the speed (m/sec) of the car at t. The left side represents Mv (dv/dx).The first term on the right side is the aerodynamics drag, \\\\\||\ ||\and the second term is the rolling resistance of the tires. Calculate how far the car travels until the speed reduces to 15 m/sec.(hint: the equation of motion may be integrated as -30 5400 v dv =E dx = x 8.276 v2+2000 Evaluate the preceding equation using Simpson rule).
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