An constant electric field, E = (31+ 4j) N/C, goes through a surface with area A = (8f – ók) m 2. (This surface can also be expressed as an area of 10 m2 with the direction of the unit vector ( 0.8Î – 0, 6k). What is the magnitude of the electric flux through this area? A) 24 N x m 2/C B) 48 N x m 2/C (c) 0.24 N × m 2/C D) 0.48 N × m ²/C E

An constant electric field, E = (31+ 4j) N/C, goes through a surface with area A = (8f – ók) m 2. (This surface can also be expressed as an area of 10 m2 with the direction of the unit vector ( 0.8Î – 0, 6k). What is the magnitude of the electric flux through this area? A) 24 N x m 2/C B) 48 N x m 2/C (c) 0.24 N × m 2/C D) 0.48 N × m ²/C E

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter15: Electric Forces And Fields

Section15.8: Electric Flux And Gauss' Law

Problem 15.9QQ: Find the electric flux through the surface in Figure 15.28. Assume all charges in the shaded area...

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