An E. coli strain where the crp gene that encodes the cAMP receptor protein (CRP), also known as the catabolite activator protein, has a mutation such that it is no longer active. In this case, the strain would no longer be able to (select all that are correct) A. Grow on minimal medium plus glucose B.Synthesize tryptophan C. Grow on minimal medium plus maltose D. Grow in a rich medium E. Grow on minimal medium plus lactose

An E. coli strain where the crp gene that encodes the cAMP receptor protein (CRP), also known as the catabolite activator protein, has a mutation such that it is no longer active. In this case, the strain would no longer be able to (select all that are correct) A. Grow on minimal medium plus glucose B.Synthesize tryptophan C. Grow on minimal medium plus maltose D. Grow in a rich medium E. Grow on minimal medium plus lactose

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter15: From Dna To Protein

Section15.1: The Connection Between Dna, Rna, And Protein

Problem 1SB

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You have two E. coli cultures. One culture is a wild-type culture, and the other contains the lacOc mutation. But, you forgot to write labels on the tubes and have mixed them up! To help you determine which culture is which, you grow each of the cultures in growth media containing either no sugar, or just lactose. Then, you perform a beta-galactosidase assay with ONPG as your enzyme substrate. You obtain the following specific activities: Culture 1, with no sugar: 147 units Culture 1, with lactose: 158 units Culture 2, with no sugar: 3.5 units Culture 2, with lactose: 164 units Which culture contains which E. coli strain? Explain how you determined this.
A number of auxotrophic mutant strains were isolated from wild-type haploid Neurospora crassa. These strains responded to the addition of certain nutritional supplements to minimal culture medium either by growth (+) or no growth (0) The data from this experiment are presented in the table below. Diagram a biochemical pathway, complete with positions of intermediates, that is consistent with the data. Indicate where in the pathway each mutant strain is blocked.
In this problem, just put the order of the intermediates on the pathway, starting with P and ending with Z and explain your reasoning. (So to get you started, notice the class 1 mutants—and there is only mutant in this class, which is mutant #5—won’t grow on minimal medium, but will grow if you give it substance Z. However, giving it substances, p, w, x, or y won’t help. This means that the gene that is mutated lies on the pathway in a place that the Z substances is to its right and all the other substances are to its left. The easiest next one to look at is the line with 2 pluses, and then the line with 3 pluses, and then the line with 4 pluses).
Assume that a series of compounds has been discovered in Neurospora. Compounds A–F appear to be intermediates in a biochemical pathway. Conversion of one intermediate to the next is controlled by enzymes that are encoded by genes. Several mutations in these genes have been identified and Neurospora strains 1–4 each contain a single mutation. Strains 1–4 are grown on minimal media supplemented with one of the compounds A–F. The ability of each strain to grow when supplemented with different compounds is shown in the table (+ = growth; o = no growth). Which biochemical pathway fits the data presented? Media Supplement Strain A B C D E F 1 o o o + + + 2 o o o o + + 3 o o o o + o 4 o o + + + + A) A → B → C → D → E → F B) A → B → C → F → D → E C) F → B → C → D → A → E D) A → B → C → D → F → E E) A → B → F → E → C → D
Which of the following would best ensure that a kidney cell and a liver cell from the same person would express different genes? Group of answer choices differences in introns unique sets of transcription factors they only have specific genes unique sets of promoters 2. Refer to the metabolic pathway illustrated. If A, B, and C are all required for growth, a strain mutant for the gene encoding enzyme A would be able to grow on medium supplemented with which of the following nutrient(s)?
For the study of alanine production by a recombinant strain of E. coli, cultivation was carried out in a benchtop bioreactor with 4.5 L of culture medium, using glucose as a limiting substrate. During the cultivation, there was no lag phase and the cells showed exponential growth for 5 hours. The following table presents the results of the analysis of ammonia and glucose consumption, and alanine accumulation throughout the cultivation. Knowing that 500 mL of a cell suspension at a concentration of 5.0 g/L (inoculum) was added to the 4.5 L of medium in the reactor and that the YX/NH3 previously determined was 7.5, calculate:a) the maximum specific growth rateb) YX/S and YP/S yield factorsc) How long would it take to reach Cx = 30 g/L if the cells continued with the exponential growth profile until the end of the culture (without nutrient deprivation or any type of inhibition)?d) Describe how the mathematical treatment of the data should be done to determine the type of product formation…
When present on the leaves of plants, the bacterium Pseudomonas syringae can promote frost damage to plants. Mutant strains, lacking the “ice” gene, have been applied to plants to try and protect the plants from wild-type P. syringae-induced frost. Assume that I am telling the truth that wild-type P. syringae nucleates ice formation at -2 °C, and provide an explanation as to why application of this altered (mutant) bacterium to plants might be a beneficial agricultural strategy in areas where morning lows occasionally dip down to 28-30 °F.
In a process of production of a recombinant protein by E. coli cells, it was observed accumulation of acetate in the culture medium. In this situation, it can be said that: (a) certainly the process in question was being conducted in anaerobiosis (B).Acetate accumulation is advantageous for the process as the acetate formation reaction generates 1 molecule of ATP (c)Knowing that decreasing the temperature of the process causes a reduction in the rate of glycolysis, this could be a strategy to reduce the accumulation of acetate (d).the acetate formed can be re-assimilated by the cell if the glyoxylate pathway is activated at some point in the culture
For bacteria that are F+, Hfr, F', and F- answer the following. a. Describe the state of the F factor. b. Which of these cells are donors? Which is the recipient? c. Which of these donors can convert exconjugants to a donor state? d. Which of these donors can transfer a donor gene to exconjugants? e. Describe the results of conjugation (i.e., changes in the recipient and the exconjugant) that allow detection of the state of the F factor in a donor strain. f. Describe a "partial diploid" and how it originates.
In a cotransformation experiment DNA was isolated from a donor strain that was proA+ and strC+ and sensitive to tetracycline. (The proA and strC genes confer the ability to synthesize proline and confer streptomycin resistance, respectively.) A recipient strain is proA− and strC− and isresistant to tetracycline. After transformation, the bacteria werefirst streaked on a medium containing proline, streptomycin, andtetracycline. Colonies were then restreaked on a medium containingstreptomycin and tetracycline. (Note: Each type of medium hadcarbon and nitrogen sources for growth.) The following resultswere obtained:70 colonies grew on the medium containing proline, streptomycin,and tetracycline, but only 2 of these 70 colonies grew whenrestreaked on the medium containing streptomycin and tetracyclinebut lacking proline.What would you expect the cotransformation frequency to be ifthe average size of the DNA fragments was 4 minutes and thetwo genes were 1.4 minutes apart?
Which of the following statements are true? □ Using multiple QS systems has the potential to enable more complex pathway control than a single QS system □ Using multiple QS systems can be an effective tool for improving product formation. □ QS is a tool that can be used only in E coli. □ The methods used in Prather’s 2019 PNAS paper included: PCR, CRISPR, HPLC and fermentation.
The reason why Beadle and Tatum observed four different categories of mutants that could not grow on media without methionine is because a. the enzyme involved in methionine biosynthesis is composed of four different subunits. b. the enzyme involved in methionine biosynthesis is present in four copies in the Neurospora genome. c. four different enzymes are involved in a pathway for methionine biosynthesis. d. a lack of methionine biosynthesis can inhibit Neurospora growth in four different ways.