An Earth satellite moves in a circular orbit 892 km above Earth's surface with a period of 102.6 min. What are (a) the speed and (b) the magnitude of the centripetal acceleration of the satellite? (a) Number i Units (b) Number i Units

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
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An Earth satellite moves in a circular orbit 892 km above Earth's surface with a period of 102.6 min. What are (a) the speed and (b) the
magnitude of the centripetal acceleration of the satellite?
(a) Number
i
Units
(b) Number
Units
Transcribed Image Text:An Earth satellite moves in a circular orbit 892 km above Earth's surface with a period of 102.6 min. What are (a) the speed and (b) the magnitude of the centripetal acceleration of the satellite? (a) Number i Units (b) Number Units
Expert Solution
Step 1

Given to us,

                     h = 892 km

             Rearth = 6.38×106 mRtotal  = 6.38×106 + 892×103         = 7.272×106 m

          T = 102.6 min = 6156 sec

 

 

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