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CalculusQ&A LibraryAn electric cable is hung between two towers that are 40 meters apart (see figure). The cable takes the shape of a catenary whose equation is as follows, where x and y are measured in meters. y = 10(ex/20 + e−x/20), −20 ≤ x ≤ 20 Find the arc length (in m) of the cable between the two towers. (Round your answer to three decimal places.) step by step instructions would be greatQuestion

Asked Feb 5, 2020

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An electric cable is hung between two towers that are 40 meters apart (see figure). The cable takes the shape of a catenary whose equation is as follows, where *x* and *y* are measured in meters.

y = 10(e^{x/20} + e^{−x/20}), −20 ≤ x ≤ 20

Find the arc length (in m) of the cable between the two towers. (Round your answer to three decimal places.)

step by step instructions would be great

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Step 1

Given:

The cable takes the shape of a catenary whose equation is,

Step 2

Obtain the derivative of *y* as shown below.

Step 3

The arc length of t...

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