# An electric cable is hung between two towers that are 40 meters apart (see figure). The cable takes the shape of a catenary whose equation is as follows, where x and y are measured in meters. y = 10(ex/20 + e−x/20), −20 ≤ x ≤ 20 Find the arc length (in m) of the cable between the two towers. (Round your answer to three decimal places.) step by step instructions would be great

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Asked Feb 5, 2020
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An electric cable is hung between two towers that are 40 meters apart (see figure). The cable takes the shape of a catenary whose equation is as follows, where x and y are measured in meters.

y = 10(ex/20 + e−x/20), −20 ≤ x ≤ 20

Find the arc length (in m) of the cable between the two towers. (Round your answer to three decimal places.)

step by step instructions would be great
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Step 1

Given:

The cable takes the shape of a catenary whose equation is,

Step 2

Obtain the derivative of y as shown below.

Step 3

The arc length of t...

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