An electric circuit has a battery with an EMF of 1.50 V. Its positive terminal is connected to its negative terminal by a copper wire in a circular loop having a radius of 0.500 m. Solve for the drift velocity in the wire if there is one free electron per copper atom.  Detailed assumptions: - The size of the cell is negligible compared to the length of the circuit. - Copper resistivity: ρ =  1.80x10-8 Ω-m  - Copper density: D =  8.96x103 kg-m-3 - Copper relative atomic mass: ma = 63.5 g/mol Express your answer in mm/s.

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An electric circuit has a battery with an EMF of 1.50 V. Its positive terminal is connected to its negative terminal by a copper wire in a circular loop having a radius of 0.500 m. Solve for the drift velocity in the wire if there is one free electron per copper atom. 

Detailed assumptions:
- The size of the cell is negligible compared to the length of the circuit.
- Copper resistivity: ρ =  1.80x10-8 Ω-m 
- Copper density: D =  8.96x103 kg-m-3
- Copper relative atomic mass: ma = 63.5 g/mol

Express your answer in mm/s.

An electric circuit has a battery with an EMF of 1.50 V. Its positive terminal is connected to its negative terminal by a copper wire in a circular loop having a radius of 0.500 m. Solve for the drift velocity in the wire if there is one free electron per copper atom.
Detailed assumptions:
- The size of the cell is negligible compared to the length of the circuit.
- Copper resistivity: p = 1.80x10-8 0-m
Copper density: D = 8.96x103 kg-m-3
Copper relative atomic mass: ma = 63.5 g/mol
Express your answer in mm/s.
Transcribed Image Text:An electric circuit has a battery with an EMF of 1.50 V. Its positive terminal is connected to its negative terminal by a copper wire in a circular loop having a radius of 0.500 m. Solve for the drift velocity in the wire if there is one free electron per copper atom. Detailed assumptions: - The size of the cell is negligible compared to the length of the circuit. - Copper resistivity: p = 1.80x10-8 0-m Copper density: D = 8.96x103 kg-m-3 Copper relative atomic mass: ma = 63.5 g/mol Express your answer in mm/s.
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