An electron is placed very close to the negative plate of a parallel plate capacitor. This electron will accelerate in the electric field produced inside the capacitor. The plates have charge Q=1x10-9C, area of A=5.0x10-4m2, and spacing of d=0.002m. What is the speed of the electron when it reaches the position x=1.70E-3m?   Assume the electron starts from rest.

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Chapter16: Electrical Energy And Capacitance
Section: Chapter Questions
Problem 7P: Oppositely charged parallel plates are separated by 5.33 mm. A potential difference of 600. V exists...
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An electron is placed very close to the negative plate of a parallel plate capacitor. This electron will accelerate in the electric field produced inside the capacitor. The plates have charge Q=1x10-9C, area of A=5.0x10-4m2, and spacing of d=0.002m. What is the speed of the electron when it reaches the position x=1.70E-3m?   Assume the electron starts from rest

Example: A proton is placed very close to the positive plate of a parallel plate capacitor. This
proton will accelerate in the electric field produced inside the capacitor. The plates have charge
Q=1x10 °C, area of A=5.0x104m², and spacing of d=0.002m. What is the speed of the proton as it
slams into the negative plate? Assume the proton starts from rest.
We could solve this problem using the constant acceleration like the last chaptersº, but we can also use
conservation of energy. Illustrated below is the situation when the proton is first placed on the positive
plate:
-1 x 10-ºC
1 × 10-°C
p+
x=0
x=d=0.002m
[8.2]
Transcribed Image Text:Example: A proton is placed very close to the positive plate of a parallel plate capacitor. This proton will accelerate in the electric field produced inside the capacitor. The plates have charge Q=1x10 °C, area of A=5.0x104m², and spacing of d=0.002m. What is the speed of the proton as it slams into the negative plate? Assume the proton starts from rest. We could solve this problem using the constant acceleration like the last chaptersº, but we can also use conservation of energy. Illustrated below is the situation when the proton is first placed on the positive plate: -1 x 10-ºC 1 × 10-°C p+ x=0 x=d=0.002m [8.2]
Question 2
Homework • Unanswered
Try this with an electron: An electron is placed near the negative plate of the capacitor in the image 8.2 above. The electron moves
(starting from rest) to position x=1.70E-3 m inside the capacitor but does not reach the positive plate. What is the electron's speed
(in m/s) at this position? Please report answers to 3 significant digits.
Respond with the correct number of significant figures in scientific notation (Use E notation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 109)
Type your numeric answer and submit
Unanswered • 2 attempts left
A Submit
Transcribed Image Text:Question 2 Homework • Unanswered Try this with an electron: An electron is placed near the negative plate of the capacitor in the image 8.2 above. The electron moves (starting from rest) to position x=1.70E-3 m inside the capacitor but does not reach the positive plate. What is the electron's speed (in m/s) at this position? Please report answers to 3 significant digits. Respond with the correct number of significant figures in scientific notation (Use E notation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 109) Type your numeric answer and submit Unanswered • 2 attempts left A Submit
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