An electron moves horizontally across the Earth’s equator at a speed of 2.50 x 106 m/s and in a direction 35.0° N of E. At this point, the Earth’s magnetic field has a direction due north, is parallel to the surface, and has a value of 3.00 x10-5 T. What is the force acting on the electron due to its interaction with the Earth’s magnetic field? (a) 6.88 x 10-18N due west (b) 6.88 x 10-18 N toward the Earth’s surface (c) 9.83 x 10-18 N toward the Earth’s surface (d) 9.83 x 10-18 N away from the Earth’s surface (e) 4.00 x 10-18 N away from the Earth’s surface.

College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter19: Magnetism
Section: Chapter Questions
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An electron moves horizontally across the Earth’s equator at a speed of 2.50 x 106 m/s and in a direction 35.0° N of E. At this point, the Earth’s magnetic field has a direction due north, is parallel to the surface, and has a value of 3.00 x10-5 T. What is the force acting on the electron due to its interaction with the Earth’s magnetic field? (a) 6.88 x 10-18N due west (b) 6.88 x 10-18 N toward the Earth’s surface (c) 9.83 x 10-18 N toward the Earth’s surface (d) 9.83 x 10-18 N away from the Earth’s surface (e) 4.00 x 10-18 N away from the Earth’s surface. 
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