An elevator loaded with tourists has a mass of 1750 kg. a.) The elevator accelerates upward (in the positive direction) from rest at a rate of 1.55 m/s2 for 2.3 s. Calculate the tension in the cable supporting the elevator in newtons b.) The elevator continues upward at constant velocity for 8.5 s. What is the tension in the cable, in Newtons, during this time? The elevator experiences a negative acceleration at a rate of 0.65 m/s2 for 2.6 s. What is the tension in the cable, in Newtons, during this period of negative accleration? c.) How far, in meters, has the elevator moved above its original starting point?

An elevator loaded with tourists has a mass of 1750 kg. a.) The elevator accelerates upward (in the positive direction) from rest at a rate of 1.55 m/s2 for 2.3 s. Calculate the tension in the cable supporting the elevator in newtons b.) The elevator continues upward at constant velocity for 8.5 s. What is the tension in the cable, in Newtons, during this time? The elevator experiences a negative acceleration at a rate of 0.65 m/s2 for 2.6 s. What is the tension in the cable, in Newtons, during this period of negative accleration? c.) How far, in meters, has the elevator moved above its original starting point?

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter6: Applications Of Newton's Laws

Section: Chapter Questions

Problem 37P: An elevator filled with passengers has a mass of 1.70103kg . (a) The elevator accelerates upward...

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Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”

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An elevator loaded with tourists has a mass of 1750 kg.

a.) The elevator accelerates upward (in the positive direction) from rest at a rate of 1.55 m/s² for 2.3 s. Calculate the tension in the cable supporting the elevator in newtons

b.) The elevator continues upward at constant velocity for 8.5 s. What is the tension in the cable, in Newtons, during this time? The elevator experiences a negative acceleration at a rate of 0.65 m/s² for 2.6 s. What is the tension in the cable, in Newtons, during this period of negative accleration?

c.) How far, in meters, has the elevator moved above its original starting point?

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