An employment recruitment firm is interested in knowing what percentage of workers is routinely late for work. An employee of the firm surveys a random sample of 65 people who have hired the firm that week to help them find employment. She asks them whether they were late for work more than 2 times a month, on average, in their last position. Of the 65 people, 17 respond that they were late for work more than 2 times a month, on average, in their last position. The employee constructs a 95% confidence interval for the proportion of workers who were late for work more than 2 times a month, on average, in their last position and obtains the interval (0.160, 0.385). Which of the following is the best example of a source of error that may cause the interval not to contain the true proportion of workers who were late more than 2 times a month, on average, in their last position? A. The sample only is representative of the people who hired the firm that week, and other workers may be different with respect to how often they are late for work. B. Some workers may have lied and said “no” because they feared that they would not be hired again, causing the true proportion to be higher than any of the values in the interval. C. Some workers may have lied and said “yes” because they wanted the employment firm to think they were regularly late to work, causing the true proportion to be lower than any of the values in the interval. D. Some workers may have said “no” because they do not know whether they were late more than 2 times a month, on average, causing the true proportion to be higher than any of the values in the interval. E. Some workers may have incorrectly thought they had been late more than 2 times a month, on average, when they actually had not, so they would answer “yes,” causing the true proportion to be lower than any of the values in the interval.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter11: Data Analysis And Probability

Section: Chapter Questions

Problem 8CR

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An employment recruitment firm is interested in knowing what percentage of workers is routinely late for work. An employee of the firm surveys a random sample of 65 people who have hired the firm that week to help them find employment. She asks them whether they were late for work more than 2 times a month, on average, in their last position. Of the 65 people, 17 respond that they were late for work more than 2 times a month, on average, in their last position. The employee constructs a 95% confidence interval for the proportion of workers who were late for work more than 2 times a month, on average, in their last position and obtains the interval (0.160, 0.385). Which of the following is the best example of a source of error that may cause the interval not to contain the true proportion of workers who were late more than 2 times a month, on average, in their last position?

A. The sample only is representative of the people who hired the firm that week, and other workers may be different with respect to how often they are late for work.

B. Some workers may have lied and said “no” because they feared that they would not be hired again, causing the true proportion to be higher than any of the values in the interval.

C. Some workers may have lied and said “yes” because they wanted the employment firm to think they were regularly late to work, causing the true proportion to be lower than any of the values in the interval.

D. Some workers may have said “no” because they do not know whether they were late more than 2 times a month, on average, causing the true proportion to be higher than any of the values in the interval.

E. Some workers may have incorrectly thought they had been late more than 2 times a month, on average, when they actually had not, so they would answer “yes,” causing the true proportion to be lower than any of the values in the interval.

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