An equation of a parabola is given.y = - Lx2(a) Find the focus, directrix, and focal diameter of the parabola.(x, y) =focusdirectrixfocal diameter(b) Sketch a graph of the parabola and its directrix.10Graph Layers«Clear AllAfter you add an object to the graph youDeletecan use Graph Layers to view and edit itsproperties.Fill-4-10 -9 -8-7 -6-5 -4 -3 -2 -11-14$ 10-2NoSolution-3-4-5-6

I am going to solve the given problem by comparing it standard form of parabola to get the required…

An equation of a parabola is given. 1,2 y = (a) Find the focus, directrix, and focal diameter of the parabola. (x, y) = ( | focus directrix focal diameter (b) Sketch a graph of the parabola and its directrix.

An equation of a parabola is given. 1,2 y = (a) Find the focus, directrix, and focal diameter of the parabola. (x, y) = ( | focus directrix focal diameter (b) Sketch a graph of the parabola and its directrix.

Intermediate Algebra

19th Edition

ISBN:9780998625720

Author:Lynn Marecek

Publisher:Lynn Marecek

Chapter11: Conics

Section11.2: Parabolas

Problem 97E: Write the equation of a parabola that opens up or down in standard form and the equation of a...

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Concept explainers

Maximization

Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.

Question

An equation of a parabola is given.
y = - Lx2
(a) Find the focus, directrix, and focal diameter of the parabola.
(x, y) =
focus
directrix
focal diameter
(b) Sketch a graph of the parabola and its directrix.
10
Graph Layers
«
Clear All
After you add an object to the graph you
Delete
can use Graph Layers to view and edit its
properties.
Fill
-4
-10 -9 -8
-7 -6
-5 -4 -3 -2 -1
1
-1
4
$ 10
-2
No
Solution
-3
-4
-5
-6

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