An Eskimo returning from a successful fishing trip pulls a sled loaded with salmon. The total mass of the sled and salmon is 50.0 kg, and the Eskimo exerts a force on the sled by pulling on the rope. Suppose the coefficient of kinetic friction between the loaded sled and snow is 0.200. (a) The Eskimo pulls the sled 4.60 m, exerting a force of 1.05 102 N at an angle of θ = 0°. Find the work done on the sled by friction, and the net work. Wfric = J Wnet = J (b) Repeat the calculation if the applied force is exerted at an angle of θ = 30.0° with the horizontal. Wfric = J Wnet = J
An Eskimo returning from a successful fishing trip pulls a sled loaded with salmon. The total mass of the sled and salmon is 50.0 kg, and the Eskimo exerts a force on the sled by pulling on the rope. Suppose the coefficient of kinetic friction between the loaded sled and snow is 0.200. (a) The Eskimo pulls the sled 4.60 m, exerting a force of 1.05 102 N at an angle of θ = 0°. Find the work done on the sled by friction, and the net work. Wfric = J Wnet = J (b) Repeat the calculation if the applied force is exerted at an angle of θ = 30.0° with the horizontal. Wfric = J Wnet = J
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter5: Newton's Laws Of Motion
Section: Chapter Questions
Problem 40PQ: A sleigh is being pulled horizontally by a train of horses at a constant speed of 8.05 m/s. The...
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An Eskimo returning from a successful fishing trip pulls a sled loaded with salmon. The total mass of the sled and salmon is 50.0 kg, and the Eskimo exerts a force on the sled by pulling on the rope. Suppose the coefficient of kinetic friction between the loaded sled and snow is 0.200.
(a) The Eskimo pulls the sled 4.60 m, exerting a force of 1.05 102 N at an angle of θ = 0°. Find the work done on the sled by friction, and the net work.
(b) Repeat the calculation if the applied force is exerted at an angle of θ = 30.0° with the horizontal.
Wfric = | J |
Wnet = | J |
(b) Repeat the calculation if the applied force is exerted at an angle of θ = 30.0° with the horizontal.
Wfric = | J |
Wnet = | J |
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