An F, generation is the result of which mating described below? Select one: O a. Randomly mating any two parents of opposite sex together. O b. Mating a true breeding female to a true breeding male. c. Mating the offspring of an F, generation back to their parents. O d. Mating any F, male to any F, female. e. Allowing the individuals from a single F, generation to mate among themselves. Clear my choice
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- Using the punnet square solve the following:Please work out this Di-Hybrid cross . -Mom is homozygous dominant for both traits -Dad is homozygous recessive for both traits Trait Key:S= Straights= CurlyL= Long l= Short 1st Question to answer ---- How many of the offspring come out straight & long? 2nd Question to answer ---- How many of the offspring come out curly & short?When a white cat was crossed with a black cat and all off springs were brown in color. How do you explain this? When a brown cat mated with a brown cat what percentage of offspring were brown. No internet copied answers, real true answers for this answer and work truly shown without internet help because it’s plagiarismIn the labrador coat color example ______ genotype would give you pure breeding black dogs (i.e. dogs that when crossed to one another would only produce puppies with black fur), ______ genotype would give you pure breeding brown dogs, and _____ genotype would give you pure breeding yellow dogs. In the potential answers the first genotype is black, the second is brown, and the third is yellow Group of answer choices A . BBEE, 2. bbEE, 3. ee with any B genotype B. BBee, 2. bbee, 3. EE with any B genotype C. BB with any E genotype, 2. bb with any E genotype, 3. bbEE D.. BBee, 2. bbee, 3. bbEE
- In cats, black coat color (B) is dominant over gray (b). A female black cat whose mother is gray mateswith a gray male. If this female has a litter of six kittens, what is the probability that four will be black?(Show your solution and put the final answer in a box).A population of hansters has a gene consisting of 90% M alleles (black) and 10% m alleles (gray). Mating is random. Determine the porpotion of offspring that will be back and the proportion that will be grayA farmer raises black and white chickens. To his surprise, when the first generation of eggs hatch all the chickens are black with white speckles throughout their feathers. What should the farmer expect when the eggs laid after interbreeding the speckled chickens hatch? a. All the offspring will be speckled. b. 75% of the offspring will be speckled, and 25% will be black. c. 50% of the offspring will be speckled, 25% will be black, and 25% will be white. d. 50% of the offspring will be black and 50% of the offspring will be white.
- biology (genetics) : Coat color in a given strain of dogs is determined by two independent genes. A dominant gene (D) determines white coat, and its recessive alleles (d) gives colored coat. In the presence of the homozygous recessive dd the coat color is black due to the presence of another dominant gene (B), or brown due to its recessive allele (b). Assuming a random mating population of dogs had the following phenotypic distribution: 448 white, 168 black, and 84 brown, find the frequency of each gene in the population.In grasshoppers, the body color of brown (B) is dominant over green (b). Also, having strong legs (L) isdominant over weak legs (l). A heterozygous brown, homozygous strong-legged male mates with a heterozygous brown, homozygous weak-legged female. Get the phenotypic and genotypic ratio of the offspring using branching method.Which of the following assumptions is NOT part of Hardy-Weinberg principle? a. no geneflow b. no mutation c. Allelic frequencies are the same in males and females d. mating is nonrandom
- Which type of breeding is depicted in the picture below? SEE PHOTO ATTACHED A. Crossbreeding B. Inbreeding C. Line breeding D. BackcrossAnswer all questions please. In guinea pigs, black coats (B) are dominant to brown coats (b). A female guinea pig that is homozygous recessive for coat color mates with a male guinea pig that is heterozygous for coat color. What percentage of their offspring will have black coats? a. 0% b. 25% c. 50% d. 75% e. 100% In guinea pigs, black coats (B) are dominant to brown coats (b). A female guinea pig that is homozygous recessive for coat color mates with a male guinea pig that is heterozygous for coat color. What would be the genotypic ratio of the F1generation? a. 3BB: 1bb b. 1BB: 2Bb: 1bb c. 2BB: 1Bb: 1bb d. 2BB: 2Bb e. 2Bb: 2bb If two guinea pigs in the F1 generation described in the question above mated, at random, what would be the likelihood that they would produce an offspring with a black coat? a. 0% b. 25% c. 50% d. 75% e. It is impossible to tell given the…In your own words compare and contrast the following; a. Hybrid vs. intermediate b. Gene vs. allele c. Dominance vs. recessive d. Genotype vs. phenotype