An HSS10x10x3/16 is used as a compression member with one end pinned and the other end fixed against rotation but free to translate. The length is 14 feet. Compute the nominal compressive strength for A500 Grade B steel (Fy = 46 ksi). Note: If this section is a slender-element compression member, you must use AISC Section E7.
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- A W21 x 101 is used as compression member with one end fixed and the other end free. The length is 10 feet. What is the nominal compressive strength if Fy 5 50 ksi? Note that this is a slender-element compression member, and the equations of AISC Section E7 must be useAn HSS 10x 8 x 3⁄16 is used as a compression member with one end pinned and the other end fixed against rotation but free to translate. The length is 12 feet. Compute the nominal compressive strength for A500 Grade B steel (Fy 5 46 ksi).A 530*150 is used as a compression member with one end fixed and the other end free. The length of the column is 3.2 m. What is the nominal compressive strength if fy=350 MPa? (please help my assigment)
- The compression member shown is made of HE300B section. If Fy is equal to 320 MPa:a) Check the section for local buckling. b) Determine the maximum compressive service load that can be supported if the live load is twice as large as the dead load.Determine the LRFD design strength (kN) of the compression member shown. The distance between the supports is 5.9 m. Use the recommended effective length factors. The column section used is W130X28.1. Use Fy = 345 MPa.The NSCP specification and A36 steel (fy =250MPa, E=200GPa). Solve the Maximum Allowable Compressive Force of the W200x35.9 if the unsupported length of the member is 5.00m , is pinned on both ends, and the radius of gyration for the weaker axis ry =40.9 mm. Hint: The answer should be in KiloNewton
- A compression member is built up from a W14x90 and a W10x49, both of A992 steel.a. Compute rx and ry for the built-up shape.b. Neglect flexural torsional buckling and compute the available strength for KxL = KyL = 30 feetusing LRFD.A W21 × 101 is used as a compression member with one end fixed and the other end free. The length is 9m. Fy = 345 MPa. 1. What are the slenderness limits for the W-section?2. What is the nominal compressive strength?Determine the flexural strength of a W14x 68 of A572 Grade 50 steel subject to a. Continuous lateral support. b. An unbraced length of 20 ft with Cb = 1.0. c. An unbraced length of 30 ft with Cb = 1.0.
- An hss10x8x3/16 is used as a compression member with one end pinned and the other end fixed against rotation but free to translate. The length is 12 feet. Compute the nominal compressive strength for a500 grade b steel (fy=46ksi). Note that this is a slender-element comoression member, and the equations of aisc section e7 must be used– A W530 × 150 is used as a compression member with one end fixed and the other end free. The length is 3 meters. What is the nominal compressive strength if Fy = 345 MPa?A W18x97 with Fy = 415 MPa is used as a compression member. The length is 4 m. The radius of gyration for the x- and y-axis are 199 mm and 67.3 mm. 3.1 Compute critical slenderness ratio if Kx = 2.2 and Ky = 1.0 3.2 What is the value of Fe 3.3 What is the nominal compressive strength of the column if its gross section area is 18 400 mm2?