An ice tray is removed from a freezer, where the ice was at a temperature of -11°C, and left on acountertop. If the mass of the ice is 0.29 kg, how much heat must be added in k to turn all the ice intoroom temperature water (that is, liquid water at 20°C)? The specific heat of water is 4.2kgCkJthe heatof fusion of water is 335kgkJand the specific heat of ice is 2.1kg°C*133.69This is a change of phase question. There are 3 cases we have to consider:1. The heat required to increase the temperature of the ice, Q12. The heat required to turn the ice into a liquid (a phase change), Q23. The heat required to raise the temperature of the now liquid water, Q3For Q1, you will use the equation Q = mcATusing the c=2.1 kJ/(kg*C). Keep in mind that thehp

Change of phase is represented as, Q=Q1+Q2+Q3=mci∆Ti+mLi+mcw∆Tw

An ice tray is removed from a freezer, where the ice was at a temperature of -11°C, and left on a countertop. If the mass of the ice is 0.29 kg, how much heat must be added in k to turn all the ice into kJ room temperature water (that is, liquid water at 20°C)? The specific heat of water is 4.2 kg C the heat kJ of fusion of water is 335 kg kJ and the specific heat of ice is 2.1 kg° C

An ice tray is removed from a freezer, where the ice was at a temperature of -11°C, and left on a countertop. If the mass of the ice is 0.29 kg, how much heat must be added in k to turn all the ice into kJ room temperature water (that is, liquid water at 20°C)? The specific heat of water is 4.2 kg C the heat kJ of fusion of water is 335 kg kJ and the specific heat of ice is 2.1 kg° C

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter1: Temperature And Heat

Section: Chapter Questions

Problem 48P: A person taking a reading of the temperature in a freezer in Celsius makes two mistakes: first...

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