An industrial bandsaw of total length L = 10.2 m and width w = 0.178 m is tightened between two wheels, each of diameter D = 1.3 m. The total force between the wheels F = 48 kN. For saw-blae steel, E = 200 GPa, v = 0.3. What thickness would you choose to minimize the tensile stress within the saw-blade? Top

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)
Section: Chapter Questions
Problem 8.5.8P: A pressurized cylindrical tank with flat ends is loaded by torques T and tensile forces P (sec...
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An industrial bandsaw of total length L = 10.2 m and width w = 0.178 m is tightened between two wheels, each of diameter D = 1.3 m. The total force between the wheels F = 48 kN. For saw-blade
steel, E = 200 GPa, v = 0.3. What thickness would you choose to minimize the tensile stress within the saw-blade?
Top
Wheel
Bottom
rWheel
t =
тт
Transcribed Image Text:An industrial bandsaw of total length L = 10.2 m and width w = 0.178 m is tightened between two wheels, each of diameter D = 1.3 m. The total force between the wheels F = 48 kN. For saw-blade steel, E = 200 GPa, v = 0.3. What thickness would you choose to minimize the tensile stress within the saw-blade? Top Wheel Bottom rWheel t = тт
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