An infinite slope in purely cohesive soil has a saturated unit weight of 20 kN/m^3 and effective cohesion of 48 kPa. It has a slope of 18 degree. The clay has a depth of 5m over ledge rock. Depth of clay is measured vertically. 1. Determine the FS against slippage. Blank 1 2. Determine the critical depth. Blank 2 3. Compute for the stability number. Blank 3 Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer

An infinite slope in purely cohesive soil has a saturated unit weight of 20 kN/m^3 and effective cohesion of 48 kPa. It has a slope of 18 degree. The clay has a depth of 5m over ledge rock. Depth of clay is measured vertically. 1. Determine the FS against slippage. Blank 1 2. Determine the critical depth. Blank 2 3. Compute for the stability number. Blank 3 Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter13: Slope Stability

Section: Chapter Questions

Problem 13.28CTP

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For the slope given below, consider the slip surface divided into thirteen slices. Based on the ordinary method of slices, calculate the Resisting Force in kN for slice #3 for long term conditions. (Acceptable tolerance = 4%). The geometry of slice #3 and the soil properties are provided in the tables below. The height of water at the middle of the slice is hw = 3.0 m hint:Given that the soil is partially saturated in Slice#3, the total weight of the slice (W) should be calculated by summing up the weight of the area that is below the water table (saturated soil) and the weight of the area located above the water table (moist soil).
4. A cut is to be made in a soil having γ = 18 kN/m3, c = 40 kPa, and φ = 15°. The cut slope makes an angle of 30°. a. If H = 6 m and θ = 15°, find the force that tend to cause sliding.b. Find the frictional force.c. Find the cohesive force.d. Find the factor of safety.e. For a factor of safety of 2.0, find the value of the critical angle along which the maximum developed cohesion occurs. f. Determine the depth of cut for a factor of safety of 2.0g. Determine the developed shear stress along the failure plane h. Determine the developed normal stress alongthe failure plane.
2. A cut is to be made in a soil that has γ = 17 kN/m3, c = 40 kPa, φ = 20°. The side of the cut slope will make an angle of 25° with the horizontal. Using a factor of safety of 2.0. a. Determine the stability number. b. Determine the stability factor. c. Determine the depth of the cut slope.
1. A trapezoidal channel with a 5-m bottom width and side slope m = 1.0 discharges 35 m3/s. The slope is 0.004 and is paved with smooth concrete (n = 0.012). a. What is the critical depth? b. What is the normal depth? c. Is it a mild slope, or steep?Hint: Compare critical depth with normal depth OR find the critical slope (??) and compare it with bed slope(?0) d. Is the depth increasing or decreasing upstream? Why would that be (e.g. a spillway, dam, etc.)?Hint: For the first part, use ????=?0−?1−??2 to show if the depth is decreasing/increasing (either by finding Fr and S, OR by simply using the values of ?, ?? and ?0 to figure out if the fraction is +/-). e. How would you conceptualize the flow – what regime (e.g., S1, S2, S3, M1, M2, M3 in Figure 10.20)? f. Determine the depth 3.3 m upstream from a section that has a measured depth of 1.69 m.Hint: If you are using MATLAB, solve the GVF differential equation (????=?0−?1−??2) and find flow depth y at location x = -3.3 m. If you are…
This is a question from slope stability bishop method Please Note i am not asking for the entire problem to be completed, i am simply seeking guidance on how to calculate slice 1 entire row that is highlighted in red. example how did we derive the values of (W) in the table. formula ....W=ybz but im not getting the values see diagram attached Question A compacted earth fill is constructed on a soft, saturated clay (figure below). The fill was compacted to an average dry unit weight of 19 kN m3 ⁄ and water content of 15%. The shearing strength of the fill was determined by CU tests on samples compacted to representative field conditions. The shear strength parameters are ?? = 45 kPa, ??′ = 34°, and ???′ = 28°. The variation of undrained shear strength of the soft clay with depth as determined by simple shear tests is shown in the figure below, and the friction angle at the critical state is ???′ = 30°. The average water content of the soft clay is 40%. Compute the factor of safety…
A 35’ high slope has an angle of 18⁰ and is composed of saturated fine grained soils. The depth to bedrock below the toe of the slope is 17’. The soil has a unit weight of 119 PCF and an effective cohesion of 200 PSF. Determine the factor of safety using Taylor’s Chart.
An infinite slope is inclined at 22 degree. A plane of failure has developed at depth of 8 m from the surface. Given dry unit weight = 18kN/m3, c’ = 12kN/m2, angle of friction = 23.5 degree and saturated unit weight = 23kN/m3. Calculate the slope factor of safety if: (i) water table exists far from the slip line
A long slope is made up of a cohesionless soil with the internal friction angle of 34°. If the water table rises to the surface of the slope, then determine the maximum possible value of the slope angle to get a factor of safety of 1.5. Take saturated unit weight as 18 kN/m3 and the unit weight of water as 10 kN/m3.
A cement lined rectangular channel 6m wide carries water at the rate of 30m3/s. Find the value of Manning’s constant, if the slope required to maintain a depth of 1.5m is 0.00126422.
Using the ordinary method of slices, find the factor of safety with respect to sliding for the following case: ?=70° , α=30°, H=12m ,?=18.4 kN/m3 ,c’=20 kN/m2, ?’=20, n’=1
A 450 slope has been excavated to a depth of 8m in saturated clay which has following properties; undrained cohesion and angle of shearing resistance are 60 kPa and Zero degrees, unit weight is 20kN/m3. Determine the factor of safety for the trial failure surface whose radius is 12 m and arc length is 18.84 m. The area of the trail wedge is 70 m2 and centre of gravity of the trail wedge is 4.5 m away from the centre of the failure surface. Consider standard value for unit weight of water.