# An investigator wants to estimate caffeine consumption in high school students.  How many students would be required to estimate the proportion of students who consume coffee?  Suppose we want the estimate to be within 5% of the true proportion with 95% confidence.          Alpha = ________                 Z= ________                  p= ________                E = ________                  n= ________

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An investigator wants to estimate caffeine consumption in high school students.  How many students would be required to estimate the proportion of students who consume coffee?  Suppose we want the estimate to be within 5% of the true proportion with 95% confidence.

Alpha = ________

Z= ________

p= ________

E = ________

n= ________

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Step 1

The provided information are:

Confidence level = 95% = 0.95

So, significance level (alpha) = 1-0.95 = 0.05

It is required that the estimate to be within 5% of the true proportion. So, the margin of error (E) = 5% = 0.05

Assume that the value of p be 0.5.

Step 2

The required value of z can be found using z-table.

Step 3

The required sample size can be...

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