An investor is looking at past trends for three plans comparing dividends paid per share. She collects sample data from each plan to compare the average dividends paid per share. Let  ? = 0.05. Plan 1 Plan 2 Plan 3 1.28 1.00 0.35 1.55 1.19 1.15 1.86 1.25 0.15 1.95 3.17 1.00 0.75 1.46 0.30 2.68 0.60 0.61 2.03 1.31 1.04 Groups Count Average Variance Plan 1 7 1.728571 0.375514 Plan 2 7 1.425714 0.667762 Plan 3 7 0.657143 0.164724 Source of Variation Sum of Squares df Mean Squares F P F crit Between Groups 4.2709 2 2.1354 5.3033 0.0155 3.5546 Within Groups 7.2480 18 0.4027       Total 11.5189 20         (a) What is the next step in the one-way ANOVA? There is not enough information, so collect more data.Stop, the results were not significant. The Tukey-Kramer post hoc test is not needed.    Stop, the results were significant. The Tukey-Kramer post hoc test is not needed.Continue to the Tukey-Kramer post hoc test, as the results were significant. (b) The Tukey-Kramer method uses the formula  (xi − xj) ± q   MSE 2   1 ni +  1 nj  .  Using the formula, what is the value of q from the table for this scenario? (Use a table. Round your answer to two decimal places.)   (c) The Tukey-Kramer method uses the formula  (xi − xj) ± q   MSE 2   1 ni +  1 nj  .  Using the formula, how many intervals need to be calculated for this scenario?

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Author:Amos Gilat
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An investor is looking at past trends for three plans comparing dividends paid per share. She collects sample data from each plan to compare the average dividends paid per share. Let 
? = 0.05.
Plan 1 Plan 2 Plan 3
1.28 1.00 0.35
1.55 1.19 1.15
1.86 1.25 0.15
1.95 3.17 1.00
0.75 1.46 0.30
2.68 0.60 0.61
2.03 1.31 1.04
Groups Count Average Variance
Plan 1 7 1.728571 0.375514
Plan 2 7 1.425714 0.667762
Plan 3 7 0.657143 0.164724
Source of Variation Sum of Squares df Mean Squares F P F crit
Between Groups 4.2709 2 2.1354 5.3033 0.0155 3.5546
Within Groups 7.2480 18 0.4027      
Total 11.5189 20        
(a)
What is the next step in the one-way ANOVA?
There is not enough information, so collect more data.Stop, the results were not significant. The Tukey-Kramer post hoc test is not needed.    Stop, the results were significant. The Tukey-Kramer post hoc test is not needed.Continue to the Tukey-Kramer post hoc test, as the results were significant.
(b)
The Tukey-Kramer method uses the formula 
(xi − xj) ± q
 
MSE
2
 
1
ni
 + 
1
nj
 
.
 Using the formula, what is the value of q from the table for this scenario? (Use a table. Round your answer to two decimal places.)
 
(c)
The Tukey-Kramer method uses the formula 
(xi − xj) ± q
 
MSE
2
 
1
ni
 + 
1
nj
 
.
 Using the formula, how many intervals need to be calculated for this scenario?
 
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