An object attached to a spring undergoes simple harmonic motion modeled by the differential equation d?y + ky = 0 where y(t) is the displacement of the mass (relative to equilibrium) at time t, m is the m dt? mass of the object, and k is the spring constant. A mass of 17 kilograms stretches the spring 0.2 meters. Use this information to find the spring constant. (Use g = 9.8 meters/second²) k = The previous mass is detached from the spring and a mass of 12 kilograms is attached. This mass is displaced 0.15 meters above equilibrium (above is positive and below is negative) and then launched with an initial velocity of 0.5 meters/second. Write the equation of motion in the form y(t) = c1 cos(wt) + c2 sin(wt). Do not leave unknown constants in your equation, and round all values to exactly 3 decimal places. y(t) =

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