An object is launched at a velocity of 20 m/s in a direction making an angle of 30° upward with the horizontal. Calculate the time to reach its maximum height. Use for gravity acceleration the value 10. Do not include units of measure in the result.

An object is launched at a velocity of 20 m/s in a direction making an angle of 30° upward with the horizontal. Calculate the time to reach its maximum height. Use for gravity acceleration the value 10. Do not include units of measure in the result.

An Introduction to Physical Science

14th Edition

ISBN:9781305079137

Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Chapter3: Force And Motion

Section: Chapter Questions

Problem 9MC: Which is true about the acceleration due to gravity? (3.5) (a) It is a universal constant. (b) It is...

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Given data

The velocity of the object launch is $v = 20 m / s$

The angle of the projectile is $θ = 30^{o}$

The accleration due to gravity is $g = 10 m / s^{2}$

The time to reach the maximum height is half of the total time of flight.

The time of flight is,

$\begin{array}{rcl} T & = & \frac{2 v \sin θ}{g} \\ = & \frac{2 (20 m / s) \sin 30^{o}}{10 m / s^{2}} \\ = & 2 s \end{array}$

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