An object is launched on the moon at 16 feet per second (f/s) from a 1152-foot tall tower. The equation for the object's height s at time t seconds after launch iss(t) = -16t^2 + 16t + 1152, where s is in feet. When does the object strike the moon’s surface and why?

An object is launched on the moon at 16 feet per second (f/s) from a 1152-foot tall tower. The equation for the object's height s at time t seconds after launch iss(t) = -16t^2 + 16t + 1152, where s is in feet. When does the object strike the moon’s surface and why?

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter3: Motion Along A Straight Line

Section: Chapter Questions

Problem 41P: Assume an intercontinental ballistic goes from rest to a suborbital speed of 6.50 km/s 60.0 s (the...

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