An object is placed in a container of liquid whose temperature is kept at 60°C. The object's initial temperature is -50°C and warms to 10°C in 30 seconds. Use Newton's Law of Cooling to find the timenecessary for the object to reach a temperature of 20°C. (Newton's Law of Cooling is given by = k(T - TE), where T(t) is the temperature of the object, TE is the temperature of the environment, and k is%3Ddta constant. Round your answer to two decimal places.)

Answered: Image /qna-images/answer/9dc43afd-b1c4-4d10-a338-566639b67b98.jpg

Answered: An object is placed in a container of…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter19: Temperature, Thermal Expansion And Gas Laws

Section: Chapter Questions

Problem 19PQ

See similar textbooks

Similar questions

During heavy exercise, the body pumps 2.00 L of blood per minute to the surface, where it is cooled by 2.00C. What is the rate of heat transfer from this forced convection alone, assuming blood has the same specific heat as water and its density is 1050kg/m3 ?
Two concrete spans that form a bridge of length L are placed end to end so that no room is allowed for expansion (Fig. P16.63a). If a temperature increase of T occurs, what is the height y to which the spans rise when they buckle (Fig. P16.63b)?
Consider a flat-plate solar collector placed on the roof of a house. The temperatures at the inner and outer surfaces of the glass cover are measured to be 33°C and 31°C, respectively. The glass cover has a surface area of 2.5 m2, a thickness of 0.6 cm, and a thermal conductivity of 0.7 W/m·K. Heat is lost from the outer surface of the cover by convection and radiation with a convection heat transfer coefficient of 10 W/m2·K and an ambient temperature of 15°C. Determine the fraction of heat lost from the glass cover by radiation.
A rectangular window in a home has a length of 1.5 m and a height of 0.80 m. If the window allows heat to escape from the home at a rate of 2,000 watts, how thick must the window be if the inside temperature of the home is 220 C and the outside temperature is 3.00C? (Assume that the coefficient of thermal conduction of glass is 0.80 W/mK.) a. 7.1 mm b. 124 mm c. 9.1 mm d. 8.1 mm e. 11 mm
Suppose a human body's core internal temperature is 37.0°C, the skin temperature is 34.0°C, the thickness of the tissues between averages 0.85 cm, and the surface area is 1.42 m2. Calculate the rate of heat conduction, in watts, out of the human body.Numeric : A numeric value is expected and not an expression.Q/Δt = __________________________________________
A thin electronic component with a surface area of 950 cm2 is cooled by having a heat sink attached on its top surface. The thermal contact conductance of the interface between the electronic component and the heat sink is 25,000 W/m2∙K. According to the manufacturer, the heat sink has combined convection and radiation thermal resistance of 1.3 K/W. If the electronic component dissipates 45 W of heat through the heat sink in a surrounding temperature of 30°C, determine the temperature of the electronic component. Does the contact resistance at the interface of the electronic component and the heat sink play a significant role in the heat dissipation?
According to Newton's law of Cooling, if a body with temperature T1 is placed in surroundings with temperature T0, different from that of T1, the body will either cool or warm to temperature T(t) after t minutes, wehre T(t)=T0+(T1-T0)e-kt. A cup of coffee with temperature of 155oF is placed in a freezer with temperature 0oF. After 10 minutes, the temperature of the coffee is 69oF. Use Newton's Law of Cooling to find the coffee's temperature after 20 minutes. After 20 minutes, the coffee will have a temperature of _____oF. (Round to the nearest integer).
Consider a very long rectangular fin attached to a flat surface such that the temperature at the end of the fin is essentially that of the surrounding air, i.e., 20°C. Its width is 5.0 cm; thickness is 1.0 mm; thermal conductivity is 200 W/m·K; and base temperature is 40°C. The heat transfer coefficient is 20 W/m2·K. Estimate the fin temperature at a distance of 5.0 cm from the base and the rate of heat loss from the entire fin.
A picture window has dimensions of 1.3 m by 2.25 m and is made of glass 4.5 mm thick. On a winter day, the outside temperature is 22° C while the inside temperature is a comfortable at 18° C. (k of glass =0.045W/m.K) Calculate the following: a) the area of the window in square metres b) the temperature gradient (AT/Ax)in kelvin/metre c) the rate of heat lost through the window by conduction in watts/metre.kelvin
A naked patient undergoes surgery in a warm room. Determine the ratio Pc /Pe, where Pc is the heat-power lost from the patient due to air convection and Pe is the heat-power lost from the patient due to evaporation. Take the skin temperature to be 32oC, the room temperature to be 29oC, the total body area to be 1.3 m2, the emissivity e = 1.0, and the convection of coefficient, q = 7.1 W/(m2.K). Take water to be lost from the patient by evaporation at a rate of 40 g/(m2.hr) and assume this to be pure water.
Consider liquid water at 1 atm. At 25◦C, the density of water is 0.997044 g cm−3 . The coefficient of thermal expansion, α, is well fitted by α = e + ft + gt2 where t is in celsius and e = −1.00871 × 10-5 K−1 , f = 1.20561 × 10-5 C −1 K−1 , and g = −5.4150 ×10-8 C−2 K−1 . What is the density of the water at 38◦C
The radius and the length of a cylindrical metal are 5.00 cm and 20.00 cm at 25 C, respectively. After it absorbed 9000 J of heat, the temperature raises from 25 C to 85 C and its length expands to 20.02 cm. Then, the cylinder was immersed to the water covered with insulator. The water initial temperature was 25 C and with mass 500 g. (Specific heat capacity of water is 4200 Jkg-1c-1 )(Heat loss through the container and cover is negligible.) Determine the volume of the cylinder at 85 C.

SEE MORE QUESTIONS

Recommended textbooks for you

Physics for Scientists and Engineers: Foundations…

Physics

ISBN:

9781133939146

Author:

Katz, Debora M.

Publisher:

Cengage Learning

Principles of Physics: A Calculus-Based Text

Physics

ISBN:

9781133104261

Author:

Raymond A. Serway, John W. Jewett

Publisher:

Cengage Learning

College Physics

Physics

ISBN:

9781938168000

Author:

Paul Peter Urone, Roger Hinrichs

Publisher:

OpenStax College

Physics for Scientists and Engineers: Foundations…

Physics

ISBN:

9781133939146

Author:

Katz, Debora M.

Publisher:

Cengage Learning

Principles of Physics: A Calculus-Based Text

Physics

ISBN:

9781133104261

Author:

Raymond A. Serway, John W. Jewett

Publisher:

Cengage Learning

College Physics

Physics

ISBN:

9781938168000

Author:

Paul Peter Urone, Roger Hinrichs

Publisher:

OpenStax College

SEE MORE TEXTBOOKS