An object moves along the x-axis so that its x-coordinate obeys the law x = 3t3 + 4t + 5. Find the time when its velocity and acceleration are equal.
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An object moves along the x-axis so that its x-coordinate obeys the law x = 3t3 + 4t + 5.
Find the time when its velocity and acceleration are equal.
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- The position of a particle moving along the x axis varies in time according to the expression x = 3t2, where x is in meters and t is in seconds. Evaluate its position (a) at t = 3.00 s and (b) at 3.00 s + t. (c) Evaluate the limit of x/t as t approaches zero to find the velocity at t = 3.00 s.A particle moves along the x axis. Its position is given by the equation x = 2 + 3t 4t2, with x in meters and t in seconds. Determine (a) its position when it changes direction and (b) its velocity when it returns to the position it had at t = 0.An object moves along the x-axis so that its x-coordinate obeys the law x = 3t3 + 4t + 5. Find the time when its velocity and acceleration are equal.
- A graph of position vs. time for a certain particle moving along the x-axis is shown. Find the average velocity in the time intervals from d) 4.00 to 7.00 s, and e) 0 to 8.00 s.A graph of position vs. time for a certain particle moving along the x-axis is shown. Find the average velocity in the time intervals from a) 0 to 2.00 s, b) 0 to 4.00 s, c) 2.00 s to 4.00 s, d) 4.00 to 7.00 s, and e) 0 to 8.00 s.During the time interval 0 < t < 1, the velocity of an object as a function of time is v = 5 + 3t^2 + 2t^3. Knowing that the object follows a rectilinear trajectory, What is the correct expression for the acceleration?
- An object moves along the xx axis and its position is given by the function g(t)=t3−7t2+3t+6. Find the acceleration at time t=−2Using SI base units, a particle’s position as a function of time is given by x(t)=(7t3+4t2+6) m. (a) At what time will the particle’s acceleration be zero? (b) Find the speed of the particle at that time.A particle starts from rest at a position x(0) = 0. Find the velocity v(t) and position y(t) of the particle if it is subjected to the following accelerations:a) a(t) = 6t3-4t2+7t-8b) a(t) = 5 +1/4 cos(1/4)t
- A particle starts from rest at a position x(0) = 0. Find the velocity v(t) and position y(t) of the particle if it is subjected to the following accelerations: a) a(t) = 6t3-4t2+7t-8 b) a(t) = 5e-5t +1/4 cos(1/4)tA particle moves along the x-axis according to the equation x = 2.00 +3.00t -1.00t^2, where x is in meters and t is in seconds. At t = 3.00s , find the acceleration of the particle.A particle moves along the x axis according to the equation x=2.00 + 3.00t - 1.00t², where x is in meters and t is in seconds. At t=3.00s, find (a) the position of the particle, (b) its velocity, and (c) its acceleration.