An object moving in a straight line with an initial velocity of 35 m/s undergoes an acceleration of a(t) = – 12t + 12 m/s², t seconds after an experiment begins. The velocity of the object after t seconds is v(t) = -6t2 + 12 + 35 x m/s The position of the object after t seconds is s(t) = -2t3 + 6t2 + 35 x m from the starting point.

An object moving in a straight line with an initial velocity of 35 m/s undergoes an acceleration of a(t) = – 12t + 12 m/s², t seconds after an experiment begins. The velocity of the object after t seconds is v(t) = -6t2 + 12 + 35 x m/s The position of the object after t seconds is s(t) = -2t3 + 6t2 + 35 x m from the starting point.

Name: An object moving in a straight line with an initial velocity of 35m/s
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: An object moving in a straight line with an initial velocity of 35m/s undergoes an acceleration of a(t) = - 12t + 12 m/s², tseconds after an experiment begins.The velocity of the object after t seconds is v(t) =-6t2 + 12 + 35x m/sThe position of the

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter2: Representing Motion

Section2.4: How Fast?

Problem 29PP

See similar textbooks

Similar questions

Consider A runner moving in a positive direction with an initial velocity of 4.6 m/s slows down at a constant rate of -1.3 m/s squared over a period of 2 seconds. What distance does she travel during this process?
An object's velocity as a function of time in one dimension is given by the expression; v(t) = 2.71t + 7.88 where are constants have proper SI Units. What is the object's velocity at t = 4.19 s?
A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = t3 − 15t2 + 72t (a) Find the velocity at time t. v(t) = (b) What is the velocity after 5 s? v(5) = ft/s (c) When is the particle at rest? t = s (smaller value) t = s (larger value) (d) When is the particle moving in the positive direction? (Enter your answer in interval notation.) t (e) Find the total distance traveled during the first 8 s.ft(f) Find the acceleration at time t. a(t) = Find the acceleration after 5 s. a(5) = ft/s2 (g) Graph the position, velocity, and acceleration functions for the first 8 s. (h) When, for 0 ≤ t < ∞, is the particle speeding up? (Enter your answer in interval notation.) When, for 0 ≤ t < ∞, is it slowing down? (Enter your answer in interval notation.)
Dr. John Paul Stapp was a U.S. Air Force officer who studied the effects of extreme acceleration on the human body. On December 10, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.00 s and was brought jarringly back to rest in only 1.40 s. Calculate his (a) acceleration in his direction of motion and (b) acceleration opposite to his direction of motion. Express each in multiples of g (9.80 m/s2) by taking its ratio to the acceleration of gravity.
You encounter a moving walkway that is 81 m long and has a speed of 2.1 m/s relative to the ground. How long would it take you to cover the 81 m length of the walkway if, once you get on the walkway, you immediately turn around and start walking in the opposite direction with a speed of 1.6 m/s relative to the walkway? Express your answer using one significant figure.
An unidentified flying object (UFO) is observed to travel a total distance of 19000 m, starting and ending at rest, over a duration of 4.23 s. Assuming the UFO accelerated at a constant rate to the midpoint of its journey and then decelerated at a constant rate the rest of the way, what was the magnitude of its acceleration? Express your answer in g s , where 1 g = 9.81 m/s^2.
A particle is moving along a line with position given by s(t)=t3−(9/2(t2 ))+6t−5 measured in meters, with t≥0 measured in minutes, and the positive direction meaning forward. a) Find the equation for the velocity at time t. Give units, and find times the times the particle is moving forward. b) Find the equation for the velocity at time t. Give units, and find times the times the particle is moving backwards. c) Find the total distance travelled by the particle. d) Find the equation of the acceleration at time t. Give the units, and find the times when the velocity of the particle is not changing. e) Find the displacement.
The Moon is about 3.8 ✕ 108 m from Earth. Traveling at the speed of light, 3.0 ✕ 108 m/s, how long does it take a laser beam to go from Earth to the Moon and back again (in s)?
A spacecraft starts from rest, and makes a journey to a destination 447000 km from its starting point. It does so by accelerating at a constant rate of 9.82 m/s^2 up to the midpoint of the journey, and then decelerates at the same constant rate of 9.82 m/s^2 for the second half of the journey, ending at rest. How long did the entire journey take?
The instantaneous speed of a particle moving along one straight line isv(t) = ate−5t, where the speed v is measured in meters per second, the time t is measured in seconds, and the magnitude of the constant a is measured in meters per second squared. What is its maximum speed, expressed as a multiple of a? (Do not include units in your answer.)
A car travels a distance d = 29 m in the positive x-direction in a time of t1 = 21.5 s. The car immediately brakes and comes to rest in t2 = 7 s.Randomized Variablesd = 29 mt1 = 21.5 st2 = 7 s What was the car's average velocity in the horizontal direction, in meters per second, during t1? What was the acceleration, in meters per second squared, during time interval t1, assuming the car started from rest and moved with a constant acceleration? What was the car's instantaneous velocity in the horizontal direction, in meters per second, when it began braking? Using the result from part (c), what was the car's horizontal component of acceleration, in meters per second squared, during the braking period?
A rocket of mass 1223 kg accelerates at 129 m/s^2 for 39 s from an initial speed of 1836 m/s. How fast will be the rocket be traveling after 39 s? No unit is required for the final answer.