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Asked Nov 15, 2019
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An object of mass m is moving with speed v0 to the right on a horizontal frictionless surface when it explodes into two pieces. Subsequently, one piece of mass 9/13 m moves with a speed of v9/13 = v0/3 to the left. The speed vf = || v4/13 || of the other piece the object is?

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Let the directi on towards be positive: Let the speed of the other object be 'v' According to the law of conservation of linear momentum Initial momentum = Final momentum 9m 4m + (v) 13 13

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