An open box of maximum volume is to be made from a square piece of material, s = 36 inches on a side, by cutting equal squares from the corners and turning up the sides (see figure). S- 2r (a) Analytically complete six rows of a table such as the one below. (The first two rows are shown.) Length and Width Height, x Volume, V 1 36 - 2(1) 1[36 – 2(1)]2 = 1156 36 – 2(2) 2[36 - 2(2)]2 = 2048 36 – 2(3) 3[36 - 2(3)]2 %3D 4 36 – 2(4) 4[36 – 2(4)]2 = 36 – 2(5) 5[36 – 2(5)]2 36 - 2(6) 6[36 – 2(6)]2 = s-2x

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 2E
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An open box of maximum volume is to be made from a square piece of material, s = 36 inches on a side, by cutting equal squares
from the corners and turning up the sides (see figure).
s- 2x
(a) Analytically complete six rows of a table such as the one below. (The first two rows are shown.)
Length and
Width
Height, x
Volume, V
36 – 2(1)
1[36 – 2(1)]? = 1156
36 – 2(2)
2[36 – 2(2)]2 = 2048
36 – 2(3) 3[36 – 2(3)]² =
4
36 – 2(4) |4[36 – 2(4)]²
36 – 2(5) 5[36 – 2(5)]² =
36 – 2(6) 6[36 – 2(6)]² =
Transcribed Image Text:An open box of maximum volume is to be made from a square piece of material, s = 36 inches on a side, by cutting equal squares from the corners and turning up the sides (see figure). s- 2x (a) Analytically complete six rows of a table such as the one below. (The first two rows are shown.) Length and Width Height, x Volume, V 36 – 2(1) 1[36 – 2(1)]? = 1156 36 – 2(2) 2[36 – 2(2)]2 = 2048 36 – 2(3) 3[36 – 2(3)]² = 4 36 – 2(4) |4[36 – 2(4)]² 36 – 2(5) 5[36 – 2(5)]² = 36 – 2(6) 6[36 – 2(6)]² =
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