Answered: An oscillator with period 3.0 ms passes…

An oscillator with period 3.0 ms passes through equilibrium at t = 6.8 ms with velocity v = -3.4 m/s. The equation of the ocillator's motion is x(t) = 1.24 cm cos ( ( 2094.39 /s ) t + 14.24

Classical Dynamics of Particles and Systems

5th Edition

ISBN:9780534408961

Author:Stephen T. Thornton, Jerry B. Marion

Publisher:Stephen T. Thornton, Jerry B. Marion

Chapter3: Oscillations

Section: Chapter Questions

Problem 3.36P

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An oscillator with period 3.0 ms passes through equilibrium at t = 6.8 ms with velocity v = -3.4 m/s. The equation of the
ocillator's motion is
X(t) = 1.24
cm cos ( ( 2094.39
/s ) t + 14.24
|

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