Analytical wavelength Analytical wavelength for red dye (nm) Calibration curve Solution 1 2 3 4 5 Dye concentration (µM) 30.20 15.10 Unknown solution 7.56 3.78 1.89 Molar absorptivity (μM-¹cm-¹) Absorbance Concentration of unknown red dye (µm) 501.4 Absorbance 0.800 0.441 0.186 0.111 0.027 0.0271 0.285 < TES

Analytical wavelength Analytical wavelength for red dye (nm) Calibration curve Solution 1 2 3 4 5 Dye concentration (µM) 30.20 15.10 Unknown solution 7.56 3.78 1.89 Molar absorptivity (μM-¹cm-¹) Absorbance Concentration of unknown red dye (µm) 501.4 Absorbance 0.800 0.441 0.186 0.111 0.027 0.0271 0.285 < TES

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter12: Atomic X-ray Spectrometry

Section: Chapter Questions

Problem 12.7QAP

See similar textbooks

Similar questions

Use the data in Figure 4.8 to estimate the ratio of radiation intensity at 10,000 Å (infrared) to that at 5000 Å (visible) from a blackbody at 5000 K. How will this ratio change with increasing temperature? Explain how this change occurs.
Potassium dichromate and potassium permanganate have overlapping absorptionspectra in 1M H2SO4 . K2Cr2O7 has an absorption maxima at 440 nm, and KMnO 4 has a band at 545nm (the maximum is actually at 525 nm, but the longer wavelength is generally used whereinterference from K2C2O7 is less). A mixture is analyzed by measuring the absorbance at these twowavelengths with the following results: A 440 =0.405, A 545 =0.712 in a 1-cm cell. The absorbances ofpure solutions of K2Cr2O7 (1x10 -3 M) and KMnO 4 (2.00x10 -4 M) in 1 M H 2 SO 4 , using the same cell gavethe following results: A Cr,440 = 0.374, A Cr,545 = 0.009, A Mn,440 =0.019, A Mn,545 = 0.475. Calculate theconcentrations of dichromate and permanganate in the sample solution.
What issues experienced with fluorescence detectors are resolved using chemiluminescence detectors?
5.4.5 Chemical microanalysis5.4.5.1 Exploitation of characteristic X-raysElectron probe microanalysis (EPMA) of bulk samples is now a routine technique for obtaining rapid, accurate analysis of alloys. A small electron probe (100 nm diameter) is used to generate X-rays from a defined area of a polished specimen and the intensity of the various characteristic X-rays measured usingeither wavelength-dispersive spectrometers (WDS) or energy-dispersive spectrometers (EDS). Typically the accuracy of the analysis is š0.1%. One of the limitations of EPMA of bulk samples is that the volume of the sample which contributes to the X-ray signal is relatively independent of the size of theelectron probe, because high-angle elastic scattering of electrons within the sample generates X-rays. The consequence of this is that the spatial resolution of EPMA is no better than ¾2 µm. In the last few years EDX detectors have been interfaced totransmission electron microscopes which are capable of operating…
Molar concentration of the dye stock solution: 2.52e-5 mol/L Operating Wavelength: 630 nm Solutions(Dilutions) Absorbance (A)(a.u.) 1 0.073 2 0.118 3 0.258 4 0.477 Using linear regression determine the absorbance/concentration relationship for the dye. [dye] =_____ x A
Why are wavlength maxima different for UV-Vis and Fluorescence?
using the following information to construct a valid hypothesis addressing the effect of pH and temperature on the hydrolysis of starch. Per bench, prepare the stock amylase enzyme solution by adding distilled water to the powdered enzyme in the flask , each bench will share one flaks of enzyme solution. per groups, turn on the spectrometer and set the wavelength to 560nm.allow the instruments to warm up for at least 10 minutes. per group, set up 17 cuvettes in a Styrofoam rack. Add 3 drops of iodine (IKI) to each coveter. per group, prepare the “black” cuvette by rapidly adding 3 mL of maltose standard solution to one of The prepared cuvettes containing IKI. Rapid addition of the maltose will mix the maltose and IKI
The drug pentobarbital is a sedative. It was extracted from a urine sample during a particular ultraviolet-visible spectrophotometric forensic analysis procedure. The extraction solvent was evaporated and the residue reconstituted in a small volume of the transparent solvent methanol. The pentobarbital solution thus obtained had a percent transmittance (%T) of 91 at the relevant wavelength of maximum absorbance. If the urine analyte concentration were halved, what would its percent transmittance be? (You may assume that the Beer-Lambert law holds). Can you show all the steps of the solution
The molar absorptivity for aqueous solutions of phenol at 211 nm is 6.17 × 103 L cm-1 mol-1. Calculate the permissible range of phenol concentrations if the transmittance is to be less than 85% and greater than 7% when the measurements are made in 1.00-cm cells.
A 1.2cm diameter glass cuvette is filled with a Cu(NH3)42+ solution that is deep blue. The cuvette is placed into a pre-blanked spectrophotometer. At 620nm, the transmittance is 23%. If the solution has molarity = 0.0133 M and path length of light through the solution = 1.2 cm, what is the value of molar absorptivity at 620 nm?
A solution with a known concentration equal to 3.4 mM gave an absorbance reading of 0.820 in a spectrophotometer. Assuming that there isa linear relationship between concentration and absorbance up to a concentration of 4.0 mM, what would the absorbance reading be for asolution with a concentration 1.5 mM?
A mixture solution of Co(II) and Ni(II) shows an absorbance of 0.500 at 500 nm. What percentage of incident light is absorbed by the solution ______(U)? Under the given conditions if 20% of the absorbance is ascribed to the contribution of Co(II), then the absorbance of Ni(II) will be ______ (V)?