anglethe signalThe" "carrier c(t) = A cos 2r10°tis%3D(РMPM or FM) " býmodulatedm(t) = 2 cos(2000rt). The deviation constant arek,= 15 rad/V and k, = 3000 Hz/V.The value of ß, and B, are respectivelyThe bandwidth in each case using carson's rule isThe value of ßp and Bf is calculated as belowBp=kplx(t)|max=1.5(2)=3ßf=kfp|x(t)|maxfm=3000x21000=6Lsing the Carson rule the valuue of handwidth for nhase modulation is obtained as below

Given: Carrier, ct=Acos2π106t Modulating signal, mt=2cos2000πt Deviation constants kp=1.5…

angle signal is Thecarrier c(t) = A cos 2r10° t modulated (PM or FM) " by the m(t) = 2 cos(2000rt). The deviation constant are = 15 rad/V and k, = 3000 Hz/V. k, The value of ß, and B, are respectively The bandwidth in each case using carson's rule is

angle signal is Thecarrier c(t) = A cos 2r10° t modulated (PM or FM) " by the m(t) = 2 cos(2000rt). The deviation constant are = 15 rad/V and k, = 3000 Hz/V. k, The value of ß, and B, are respectively The bandwidth in each case using carson's rule is

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

angle
the signal
The" "carrier c(t) = A cos 2r10°t
is
%3D
(РM
PM or FM) " bý
modulated
m(t) = 2 cos(2000rt). The deviation constant are
k,
= 15 rad/V and k, = 3000 Hz/V.
The value of ß, and B, are respectively
The bandwidth in each case using carson's rule is
The value of ßp and Bf is calculated as below
Bp=kplx(t)|max=1.5(2)=3ßf=kfp|x(t)|maxfm=3000x21000=6
Lsing the Carson rule the valuue of handwidth for nhase modulation is obtained as below

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