Please help Answer:12. Target Reaction:Zn(s) + 1/8S,(s) + 20 (g) → ZnSO (s)Zn(s) + 1/8S (s)→ ZnS(s)2ZnS(s) + 30 (g) → 2ZnO(s) + 2SO (g)AH = -183.92 kJStep Reactions:AH = -927 kJ2S0_(g) + O_(g) → 2SO_(g)ZnO(s) + SO (g) → ZnSO (s)AH = -196.04 kJAH = -230.32 kJAnswer:

Calculate ∆H for the required reaction--

Answer: 12. Target Reaction: 1/88,(s) + 20 (g) → ZnSO (s) Step Reactions: Zn(s) + 1/8S (s) → ZnS(s) 8. AH = -183.92 kJ 2ZnS(s) + 30 (g) 2ZnO(s) + 2SO_(g) 2S0 (g) + O (g) → 280 (g) AH = -927 kJ 2. AH = -196.04 kJ %3D 3. ZnO(s) + SO (g) → ZnSO (s) AH = -230.32 kJ %3D Answer:

Answer: 12. Target Reaction: 1/88,(s) + 20 (g) → ZnSO (s) Step Reactions: Zn(s) + 1/8S (s) → ZnS(s) 8. AH = -183.92 kJ 2ZnS(s) + 30 (g) 2ZnO(s) + 2SO_(g) 2S0 (g) + O (g) → 280 (g) AH = -927 kJ 2. AH = -196.04 kJ %3D 3. ZnO(s) + SO (g) → ZnSO (s) AH = -230.32 kJ %3D Answer:

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter2: Chemical Formulas, Equations, And Reaction Yields

Section: Chapter Questions

Problem 46AP

See similar textbooks

Similar questions

حد يدبرلنا طريقة حل فرع C A research group discovers a new version of happyase, which they call happyase*, that catalyzes the chemical reaction HAPPY ⇌ SAD. The researchers begin to characterize the enzyme. (a) In the first experiment, with [Et] at 4 nM, they find that the Vmax is 1.6 μM s−1. Based on this experiment, what is the kcat for happyase*? (Include appropriate units.) (b) In another experiment, with [Et] at 1 nM and [HAPPY] at 30 μM, the researchers find that V0 = 300 nM s−1. What is the measured Km of happyase* for its substrate HAPPY? (Include appropriate units.) (c) Further research shows that the purified happyase used in the first two experiments was actually contaminated with a reversible inhibitor called ANGER. When ANGER is carefully removed from the happyase preparation and the two experiments repeated, the measured Vmax in (a) is increased to 4.8 μM s−1, and the measured Km in (b) is now 15 μM. For the inhibitor ANGER, calculate the values of α and α′. . (d)…
Fast pls solve this question correctly in 5 min pls I will give u like for sure Mass of Copper: 0.99g Mass of Aluminum: 0.35g Mass of CuCl2: 2.55g 2Al(s) + 3CuCl2 * 2H2O (Hydrate molecule) --→ AlCl3(aq) + 3Cu + 6H2O Please calculate the limiting reagent and show the steps.
A political candidate fighting for a smoke-free environment conducts an experiment in a room containing 1400 cubic feet of air that is initially free of carbon monoxide. Beginning at time t=0, cigarette smoke containing 4% carbon monoxide is introduced into the room at the rate of 0.1 cubic foot perminute, and the well-circulated mixture is allowed to leave the room at the same rate. If carbon monoxide levels in the air reach 0.012%, it is harmful to the human body. Find the time at which this unhealthy level is reached.
1) Commercial fuming Sulphuric acid (Oleum-H2S2O6) is 99.9% solution. Please convert it into molarity.2) Find out the Volume (dm3) of product (gas) at RTP when 0.58 M, 150 mL NaOH (aq.) reacts with 350 mL, 0.25 NH4Cl.
Using the following chemical equation and data: 3A + B + 2C --> D + 2E Experiment Initial [A] Initial [B] Initial [C] Initial Rate 1 1.0 x 10-2 4.0 x 10-3 2.0 x 10-2 5 mM/s 2 1.0 x 10-2 8.0 x 10-3 2.0 x 10-2 10 mM/s 3 2.0 x 10-2 8.0 x 10-3 2.0 x 10-2 40 mM/s 4 2.0 x 10-2 8.0 x 10-3 1.0 x 10-2 40 mM/s Determine the initial rate of reaction if the initial concentrations of A, B, C are 3 x 10-2 M, 5 x 10-3 M, 5 x 10-5 M, respectively, for the reaction.
Using the following chemical equation and data: 3A + B + 2C --> D + 2E Experiment Initial [A] Initial [B] Initial [C] Initial Rate 1 1.0 x 10-2 4.0 x 10-3 2.0 x 10-2 5 mM/s 2 1.0 x 10-2 8.0 x 10-3 2.0 x 10-2 10 mM/s 3 2.0 x 10-2 8.0 x 10-3 2.0 x 10-2 40 mM/s 4 2.0 x 10-2 8.0 x 10-3 1.0 x 10-2 40 mM/s Calculate the specific rate constant (k).
Using the following chemical equation and data: 3A + B + 2C --> D + 2E Experiment Initial [A] Initial [B] Initial [C] Initial Rate 1 1.0 x 10-2 4.0 x 10-3 2.0 x 10-2 5 mM/s 2 1.0 x 10-2 8.0 x 10-3 2.0 x 10-2 10 mM/s 3 2.0 x 10-2 8.0 x 10-3 2.0 x 10-2 40 mM/s 4 2.0 x 10-2 8.0 x 10-3 1.0 x 10-2 40 mM/s Determine the rate equation.
Initial temp: 19.06 C 0.5 M concentration 200 mL of HCl and 200 mL of NaOH are combined in an insulated container. H+(aq) + OH-(aq) - - -> H2O (l) ∆H H++ = 0, ∆H OH−− = -230 kJ/mol, ∆H H2O = -286 kJ/mol ∆H reactants = ∆H H++ + ∆H OH−− = -230 + 0 = -230 kJ/mol ∆H reactants = -286 kJ/mol - ( -230 kJ/mol) = -56 kJ/mol H+ (aq) + OH− (aq) - - -> H2O (l) Using your observations and the stoichiometric relationships of the reaction, determine the number of moles that react. Show/upload your work.
I was told to repost this question, because I got the explanations for a-c. I just need d explained. 7. Sulfuryl chloride, SO2Cl2, is a highly reactive gaseous compound. When heated, it decomposes as follows: SO2Cl2 (g) ⇌ SO2 (g) + Cl2 (g). This decomposition is endothermic. A sample of 3.509 grams of SO2Cl2 is placed in an evacuated 1.00-L bulb and the temperature is raised to 375 K. a. What would be the pressure (in atm) in the bulb if no dissociation of the SO2Cl2(g) occurred? b. When the system has come to equilibrium at 375 K, the total pressure in the bulb is found to be 1.43 atm. Calculate the partial pressures of SO2, Cl2, and SO2Cl2 at equilibrium. c. Give the expression for the equilibrium constant (either Kp or KC) for the decomposition of SO2Cl2(g) at 375 K. Calculate the value of the equilibrium constant you have selected. d. If the temperature were raised to 500 K, what effect would this have on the equilibrium constant? Explain in 1-2 sentences.
QUESTION 5 Calculate ΔG°rxn for the reaction below at 25°C. CH3CH2OH (ℓ) + 3O2 (g) → 2CO2 (g) + 3H2O (ℓ) Report your answer in kJ/mol to one decimal place. ΔH°f (kJ/mol) S° (J/(K·mol)) CH3CH2OH (ℓ) -277.7 160.7 O2 (g) 0 205.14 CO2 (g) -393.5 213.7 H2O (ℓ) -285.8 69.1
Carbonic anhydrase is one of the fastest enzymes known. If 10 µg of this enzyme catalyzes the conversion of 0.30 g of CO2 to bicarbonate in 1 minute at 37˚C. What is the Kcat value for this enzyme in min -1?
QUESTION 4 Calculate ΔG°rxn for the reaction below at 25.0°C. 2H2O2 (ℓ) → 2H2O (ℓ) + O2 (g) Report your answer in kJ/mol to two decimal places. ΔG°f (kJ/mol) H2O2 (ℓ) -120.35 H2O (ℓ) -237.13