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Answer the given problem below by following in hypothesis testing. Sample problem: Determine the weight of the students before and during the quarantine. Did the students lose more fat before the quarantine? Weight before quarantine: sample mean = 5.9 kg sample standard deviation = 4.1 kg sample size = n = 42 standard error = SEM1 = 4.1/ √42 = 0.633 Weight during quarantine: sample mean = 4.1 kg sample standard deviation = 3.7 kg sample size = n = 47 standard error = SEM2 = 3.7/ √47 = 0.540 measure of variability = sq root [(0.633)2 + (0.540)2] = 0.83 1. Determine the p-value = 0.03 (LOS= 95%; α=0.05) 2. Make a decision 3. Conclusion

Answer the given problem below by following in hypothesis testing. Sample problem: Determine the weight of the students before and during the quarantine. Did the students lose more fat before the quarantine? Weight before quarantine: sample mean = 5.9 kg sample standard deviation = 4.1 kg sample size = n = 42 standard error = SEM1 = 4.1/ √42 = 0.633 Weight during quarantine: sample mean = 4.1 kg sample standard deviation = 3.7 kg sample size = n = 47 standard error = SEM2 = 3.7/ √47 = 0.540 measure of variability = sq root [(0.633)2 + (0.540)2] = 0.83 1. Determine the p-value = 0.03 (LOS= 95%; α=0.05) 2. Make a decision 3. Conclusion

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section: Chapter Questions
Problem 8SGR
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Answer the given problem below by following in hypothesis testing.

Sample problem: Determine the weight of the students before and during the quarantine. Did the students lose more fat before the quarantine?

Weight before quarantine:

sample mean = 5.9 kg

sample standard deviation = 4.1 kg sample size = n = 42

standard error = SEM1 = 4.1/ √42 = 0.633

Weight during quarantine:

sample mean = 4.1 kg

sample standard deviation = 3.7 kg sample size = n = 47

standard error = SEM2 = 3.7/ √47 = 0.540

measure of variability = sq root [(0.633)2 + (0.540)2] = 0.83

1. Determine the p-value = 0.03 (LOS= 95%; α=0.05)

2. Make a decision

3. Conclusion          

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