Apply Euler's method twice to approximate the solution to the initial value problem on the interval 0,- , first with step size h = 0.25, then with step size h = 0.1. Compare the three-decimal-place values of the two approximations at x = with the value of y of the actual solution. y' =y - 4x + 1, y(0) = 2, y(x) = 3 + 4x - e* The Euler approximation when h = 0.25 of y is 3.438. (Type an integer or decimal rounded to three decimal places as needed.) The Euler approximation when h = 0.1 of y is 3.389'. (Type an integer or decimal rounded to three decimal places as needed.) The value of 2 using the actual solution is 3.351. (Type an integer or decimal rounded to three decimal places as needed.) The approximation 3.389 , using the lesser value of h, is closer to the value of y found using the actual solution. (Type an integer or decimal rounded to three decimal places as needed.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Apply Euler's method twice to approximate the solution to the initial value problem on the interval 0,
1
first with step size h = 0.25, then with step size h = 0.1. Compare the three-decimal-place values of the two
1
with the value of y
2
approximations at x =
of the actual solution.
у' -у-4x+1, у(0) %3D2, у(x) %3 3 +4x - е
The Euler approximation when h = 0.25 of y
1
is 3.438'.
(Type an integer or decimal rounded to three decimal places as needed.)
The Euler approximation when h = 0.1 of y
is 3.389.
2
(Type an integer or decimal rounded to three decimal places as needed.)
The value of y
using the actual solution is 3.351
(Type an integer or decimal rounded to three decimal places as needed.)
1
The approximation 3.389 , using the lesser value of h, is closer to the value of y
found using the actual solution.
2
(Type an integer or decimal rounded to three decimal places as needed.)
Transcribed Image Text:Apply Euler's method twice to approximate the solution to the initial value problem on the interval 0, 1 first with step size h = 0.25, then with step size h = 0.1. Compare the three-decimal-place values of the two 1 with the value of y 2 approximations at x = of the actual solution. у' -у-4x+1, у(0) %3D2, у(x) %3 3 +4x - е The Euler approximation when h = 0.25 of y 1 is 3.438'. (Type an integer or decimal rounded to three decimal places as needed.) The Euler approximation when h = 0.1 of y is 3.389. 2 (Type an integer or decimal rounded to three decimal places as needed.) The value of y using the actual solution is 3.351 (Type an integer or decimal rounded to three decimal places as needed.) 1 The approximation 3.389 , using the lesser value of h, is closer to the value of y found using the actual solution. 2 (Type an integer or decimal rounded to three decimal places as needed.)
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