Applying the KCL at top node we get: e e e R + X, + xis S e e e + 3k j4k =5Z – 20° mA - j2k O e( -i+)=52 – 20' 1 3 4 e(0.4164Z36. 897°)=5Z – 20° - e=12Z – 56. 897° V
Applying the KCL at top node we get: e e e R + X, + xis S e e e + 3k j4k =5Z – 20° mA - j2k O e( -i+)=52 – 20' 1 3 4 e(0.4164Z36. 897°)=5Z – 20° - e=12Z – 56. 897° V
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter4: Transmission Line Parameters
Section: Chapter Questions
Problem 4.8MCQ: An ac resistance is higher than a dc resistance. True False
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How did We get the e=12∠-56.897° V
Please explain to me.
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