As a result of the collision, the second cart acquires a speed of 2.4 m/s

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter9: Linear Momentum And Collisions
Section: Chapter Questions
Problem 9.4OQ: A 2-kg object moving to the right with a speed of 4 m/s makes a head-on, elastic collision with a...
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Calculate the distance traveled by the second cart during the 5.0 s interval after the collision.

3.0 m/s
2.0 kg
A 2.0 kg frictionless cart is moving at a constant speed of 3.0 m/s to the right on a horizontal surface, as
shown above, when it collides with a second cart of undetermined mass m that is initially at rest. The
magnitude of the force Fof the collision as a function of time tis shown in the graph below, where t= 0 is
the instant of initial contact. As a result of the collision, the second cart acquires a speed of 2.4 m/s to the
right. Assume that friction is negligible before, during, and after the collision.
4,000
Force (N)
2,000
1
2
Time (ms)
Transcribed Image Text:3.0 m/s 2.0 kg A 2.0 kg frictionless cart is moving at a constant speed of 3.0 m/s to the right on a horizontal surface, as shown above, when it collides with a second cart of undetermined mass m that is initially at rest. The magnitude of the force Fof the collision as a function of time tis shown in the graph below, where t= 0 is the instant of initial contact. As a result of the collision, the second cart acquires a speed of 2.4 m/s to the right. Assume that friction is negligible before, during, and after the collision. 4,000 Force (N) 2,000 1 2 Time (ms)
After the collision, the second cart eventually experiences a ramp, which it traverses with no frictional
losses. The graph below shows the speed v of the second cart as a function of time t for the next 5.0 s,
where t = 0 is now the instant at which the carts separate.
2.0
Speed v (m/s)
1.0
Time (s)
Transcribed Image Text:After the collision, the second cart eventually experiences a ramp, which it traverses with no frictional losses. The graph below shows the speed v of the second cart as a function of time t for the next 5.0 s, where t = 0 is now the instant at which the carts separate. 2.0 Speed v (m/s) 1.0 Time (s)
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