As shown in Figure below, a flexible belt placed around a rotating drum of 120-mm radius acts as a brake when the arm ABCD is pulled down by the force P. The coefficient of kinetic friction between the belt and the drum is 0.20 determine the force P that would result in a braking torque of 12,000-N.mm, assuming that the drum is rotating counterclockwise. Neglect the weight of the brake arm. 60° 60 | B 60 - 120 – 60 mm mm 120 mm

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.49P
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Solve each of the following problems indicated below. Present your complete-detail solution including the free- body diagrams. Box your only final answer.

As shown in Figure below, a flexible belt placed around a rotating drum
of 120-mm radius acts as a brake when the arm ABCD is pulled down
by the force P. The coefficient of kinetic friction between the belt and
the drum is 0.20 determine the force P that would result in a braking
torque of 12,000-N.mm, assuming that the drum is rotating
counterclockwise. Neglect the weight of the brake arm.
120 mm
60°
60°
D
60
120
60
mm
mm
mm
Transcribed Image Text:As shown in Figure below, a flexible belt placed around a rotating drum of 120-mm radius acts as a brake when the arm ABCD is pulled down by the force P. The coefficient of kinetic friction between the belt and the drum is 0.20 determine the force P that would result in a braking torque of 12,000-N.mm, assuming that the drum is rotating counterclockwise. Neglect the weight of the brake arm. 120 mm 60° 60° D 60 120 60 mm mm mm
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