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A small bag of sand is released from an ascending hot‑air balloon whose constant, upward velocity is ?0=2.95 m/s. Knowing that at the time of the release the balloon was 57.8 m above the ground, determine the time ? it takes for the bag to reach the ground from the moment of its release. Use ?=9.81 m/s^2.
? = _____________ s
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- A small bag of sand is released from an ascending hot‑air balloon whose constant, upward velocity is ?0=2.15 m/sv0=2.15 m/s. Knowing that at the time of the release the balloon was 58.8 m58.8 m above the ground, determine the time ?τ it takes for the bag to reach the ground from the moment of its release. Use ?=9.81 m/s2.A small bag of sand is released from an ascending hot‑air balloon whose constant, upward velocity is v0=2.75 m/s. Knowing that at the time of the release the balloon was 74.3 m above the ground, determine the time τ it takes for the bag to reach the ground from the moment of its release. Use ?=9.81 m/s2. τ =A lead ball is dropped into a lake from a diving board 5.0 m above the water. After entering the water, it sinks to the bottom with a constant velocity equal to the velocity with which it hit the water. The ball reaches the bottom 3.0 safter it is released. How deep is the lake? Visual Representation• Draw a sketch showing important points in the motion• Establish a coordinate system and define symbols• Draw a motion diagram• List knowns and desired unknowns Mathematical Representation• Identify and write down the relevant equation(s), using the symbols defined in your sketch• Solve equation(s) for the desired unknown• Substitute in the known values, including units, and calculate unknown value• Check units and assess if your answer is reasonable
- A river flows due south with a speed of 4.00 m/s. A man steers a motorboat across the river; his velocity relative to the water is 3.80 m/s due east. The river is 790 m wide. How much time is required for the man to cross the river? (Express your answer in seconds.) How far south of his starting point will he reach the opposite bank? (Express your answer in meters.)A pirate ship launches a cannon ball with an initial speed of 200 m/s. The ball is to strike an enemy ship that is exactly 3.0 km from the cannon. What is the minimum time-of-flight for the ball? Options 8 s 16 s 14 s 19 s 21 s 24 sKEY TERMS 1. physics (intro) 2. position (2.1) 3. motion 4. scalar (2.2) 5. vector 6. average speed 7. distance 8. instantaneous speed 9. average velocity 10. displacement 11. instantaneous velocity 12. acceleration (2.3) 13. average acceleration 14. acceleration due to gravity 15. free fall 16. terminal velocity 17. centripetal acceleration (2.4) 18. projectile motion (2.5) For each of the following items, fill in the number of the appropriate Key Term from the preceding list. b. _____ Difference between final and initial velocities divided by time
- KEY TERMS 1. physics (intro) 2. position (2.1) 3. motion 4. scalar (2.2) 5. vector 6. average speed 7. distance 8. instantaneous speed 9. average velocity 10. displacement 11. instantaneous velocity 12. acceleration (2.3) 13. average acceleration 14. acceleration due to gravity 15. free fall 16. terminal velocity 17. centripetal acceleration (2.4) 18. projectile motion (2.5) For each of the following items, fill in the number of the appropriate Key Term from the preceding list. r. _____ Displacement/travel timeKEY TERMS 1. physics (intro) 2. position (2.1) 3. motion 4. scalar (2.2) 5. vector 6. average speed 7. distance 8. instantaneous speed 9. average velocity 10. displacement 11. instantaneous velocity 12. acceleration (2.3) 13. average acceleration 14. acceleration due to gravity 15. free fall 16. terminal velocity 17. centripetal acceleration (2.4) 18. projectile motion (2.5) For each of the following items, fill in the number of the appropriate Key Term from the preceding list. a. _____ Zero acceleration in free fallThe height of a projectile fired straight up in the air with an initial velocity of 64 ft/s is h = 64t - 16t2, where h is height in feet and t is time in seconds. The table represents the data for another projectile. Which projectile goes higher? How much higher? Table Data Time (t) Height (h) 0.5 20 1 32 1.5 36 2 32
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