The height of a projectile fired straight up in the air with an initial velocity of 64 ft/s is h = 64t - 16t2, where h is height in feet and t is time in seconds. The table represents the data for another projectile. Which projectile goes higher? How much higher?

The height of a projectile fired straight up in the air with an initial velocity of 64 ft/s is h = 64t - 16t2, where h is height in feet and t is time in seconds. The table represents the data for another projectile. Which projectile goes higher? How much higher?

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Vectors

Section: Chapter Questions

Problem 3.24P: A map suggests that Atlanta is 730 miles in a direction of 5.00 north of cast from Dallas. The same...

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Question

The height of a projectile fired straight up in the air with an initial velocity of 64 ft/s is h = 64t - 16t², where h is height in feet and t is time in seconds. The table represents the data for another projectile. Which projectile goes higher? How much higher?

Table Data

Time (t)	Height (h)
0.5	20
1	32
1.5	36
2	32

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