Assignment 1 1. Determine the positive root of f (x) x3 + 2x – 2 = 0 using the Newton- Raphson method and an initial guess of x = 0. 2. Determine the root of f (x) = sin x – e-* = 0 using the Newton- Raphson method in the interval [0,1] up to four decimal places. Answer = 0.5885. 3. Using Newton- Raphson method, find the real root, correct for three decimal places, of the equation sinx = x/2 given that the root lies between- and Answer = 1.896

Assignment 1 1. Determine the positive root of f (x) x3 + 2x – 2 = 0 using the Newton- Raphson method and an initial guess of x = 0. 2. Determine the root of f (x) = sin x – e-* = 0 using the Newton- Raphson method in the interval [0,1] up to four decimal places. Answer = 0.5885. 3. Using Newton- Raphson method, find the real root, correct for three decimal places, of the equation sinx = x/2 given that the root lies between- and Answer = 1.896

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter5: Analysis Of Convection Heat Transfer

Section: Chapter Questions

Problem 5.2P: 5.2 Evaluate the Prandtl number from the following data: , .

See similar textbooks

Similar questions

5.2 Evaluate the Prandtl number from the following data: , .
Calculate the answer, and present in scientific notation. (0.32)(14.50)(120)= (14.1)/(0.005)= (3.9)(6.05)(420)=
Make the statistical analysis for all of data given into table below using Excel program. N number =9 COUNT X 1 0.244(N) 2 0.234(N) 3 0.247(N) 4 0.231(N) 5 0.235(N) 6 0.244(N) 7 0.230(N) 8 0.233(N) 9 0.244(N) 10 0.241(N) 11 0.247(N) 12 0.231(N)
2. Answer the question completely and write down the given, required and formula that had been used. Provide graph and accurate/comple solution. The value are: V- 1 X- 5 W- 7 Y- 6 Z- 8
MECHANICAL ENGINEERING UPVOTE WILL BE GIVEN. PLEASE WRITE THE COMPLETE SOLUTIONS LEGIBLY. SHOW THE STEP-BY-STEP PROCESS WITH SHORT COMMENT/EXPLANATION. ANSWER IN 4 DECIMAL PLACES. Two gaseous streams containing the same fluid enters a mixing chamber and leaves as a single stream. For the first gas the entrance conditions are A1=500 cm², v1=230 m/s, p1=1.60 kg/m³. For the second gas the entrance conditions are A2= 300 cm³, m2=8.84 kg/s, v2=0.502 m³/kg. The exit stream conditions is v3=130 m/s and v3=0.437 m3/kg. Determine the following: (a) the total mass flow leaving the chamber (kg/sec) (b) the velocity of the gas at 2. (m/sec)
Please solve part B please!! thank youu will rate your answer!ᴘᴀʀᴛ ᴀ.ᴀ ᴋɴᴜᴄᴋʟᴇ ᴊᴏɪɴᴛ ɪꜱ ᴛᴏ ʙᴇ ᴀxɪᴀʟʟʏ ʟᴏᴀᴅᴇᴅ ᴡɪᴛʜ ᴀ ᴛᴇɴꜱɪʟᴇ ʟᴏᴀᴅ ꜰ. ᴛʜᴇ ᴀꜱꜱᴇᴍʙʟʏ ᴏꜰ ᴘᴀʀᴛꜱ ᴀɴᴅ ᴛʜᴇɪʀ ᴠᴀʀɪᴀʙʟᴇᴅɪᴍᴇɴꜱɪᴏɴꜱ ᴀʀᴇ ꜱʜᴏᴡɴ ɪɴ ᴛʜᴇ ꜰɪɢᴜʀᴇ ʙᴇʟᴏᴡ. ᴡʀɪᴛᴇ ᴛʜᴇ ꜱᴛʀᴇꜱꜱ ᴇQᴜᴀᴛɪᴏɴ ᴀᴛ ᴇᴀᴄʜ ᴏꜰ ᴛʜᴇ ᴘᴏꜱꜱɪʙʟᴇ ʟᴏᴄᴀᴛɪᴏɴꜱ ᴏꜰ ꜰᴀɪʟᴜʀᴇ. ɪᴅᴇɴᴛɪꜰʏ ᴇᴀᴄʜ ꜱᴛʀᴇꜱꜱ ᴀɴᴅ ᴡʀɪᴛᴇ ɪᴛꜱ ᴇQᴜᴀᴛɪᴏɴ ɪɴ ᴛᴇʀᴍꜱ ᴏꜰ ᴛʜᴇ ʟᴏᴀᴅ ꜰ, ᴀɴᴅ ᴛʜᴇ ɢɪᴠᴇɴ ᴅɪᴍᴇɴꜱɪᴏɴꜱ ᴀ, ʙ, ᴄ, ᴅ, ᴋ, ᴍ ᴀɴᴅ ɴ. (ᴇxᴀᴍᴘʟᴇ: ᴛᴇɴꜱɪʟᴇ ꜱᴛʀᴇꜱꜱ ᴀᴛ ᴛʜᴇ ʀᴏᴅ ᴏꜰ ᴛʜᴇ ᴋɴᴜᴄᴋʟᴇ ᴊᴏɪɴᴛ: ꜱᴛ = 4ꜰ/Πᴅ2). ᴅᴏɴ’ᴛ ᴜꜱᴇ ᴠᴀʀɪᴀʙʟᴇꜱ ᴛʜᴀᴛ ᴀʀᴇ ɴᴏᴛ ᴅᴇꜰɪɴᴇᴅ ɪɴ ᴛʜᴇ ᴊᴏɪɴᴛ ᴅᴇꜱᴄʀɪʙᴇᴅ ʙᴇʟᴏᴡ. ꜱᴜᴘᴘᴏʀᴛ ᴇᴀᴄʜ ᴏꜰ ᴛʜᴇ ꜱᴛʀᴇꜱꜱ ᴇQᴜᴀᴛɪᴏɴꜱ ʙʏ ᴍᴇᴀɴꜱ ᴏꜰ ᴀɴ ɪꜱᴏᴍᴇᴛʀɪᴄ ᴅʀᴀᴡɪɴɢ ɪɴᴅɪᴄᴀᴛɪɴɢ ᴛʜᴇ ᴘᴀʀᴛ ᴀɴᴅ ɪᴛꜱ ᴅɪᴍᴇɴꜱɪᴏɴꜱ ᴛʜᴀᴛ ᴍɪɢʜᴛ ʜᴀᴠᴇ ꜰᴀɪʟᴇᴅ ᴅᴜᴇ ᴛᴏ ᴏᴠᴇʀꜱᴛʀᴇꜱꜱɪɴɢ. ꜰᴏʀ ᴛʜᴇ ʙᴇɴᴅɪɴɢ ꜱᴛʀᴇꜱꜱ ɪɴ ᴛʜᴇ ᴘɪɴ, ᴄᴏɴꜱɪᴅᴇʀ ᴛʜᴇ ʟᴏᴀᴅꜱ ᴛᴏ ʙᴇ ᴜɴɪꜰᴏʀᴍʟʏ ᴅɪꜱᴛʀɪʙᴜᴛᴇᴅ ᴀᴛ ᴛʜᴇ ᴄᴇɴᴛᴇʀ ᴏꜰ ᴛʜᴇ ᴄᴏᴛᴛᴇʀ ᴀɴᴅ ᴜɴɪꜰᴏʀᴍʟʏ ᴠᴀʀʏɪɴɢ ᴀᴛ ᴛʜᴇ ᴋɴᴜᴄᴋʟᴇ ᴇɴᴅ. ɴᴇɢʟᴇᴄᴛ ᴛʜᴇ ᴘʀᴇꜱᴇɴᴛ ᴏꜰ ᴛʜᴇ ꜰɪʟʟᴇᴛꜱ ɪɴ ᴄᴏɴꜱɪᴅᴇʀɪɴɢ ᴛʜᴇ ᴅɪᴍᴇɴꜱɪᴏɴꜱᴘᴀʀᴛ ʙ.ᴜꜱɪɴɢ ᴛʜᴇ ꜱᴛʀᴇꜱꜱ ᴇQᴜᴀᴛɪᴏɴꜱ ꜰᴏʀᴍᴇᴅ ɪɴ ᴘᴀʀᴛ ᴀ, ᴅᴇꜱɪɢɴ ᴛʜᴇ ᴊᴏɪɴᴛ ʙʏ ꜱᴘᴇᴄɪꜰʏɪɴɢ…
Using trapezoidal rule integration with 2 equal sized sub-intervals, find the area under the curve defined by the polynomial y = 0.04x5 + 0.5x3 + 38 between limits of 4.7 and 11.0. Give your answer to a precision of at least 3 significant figures.
Cardiologists use the short-range scaling exponent α1, which measures the randomness of heart rate patterns, as a tool to assess risk of heart attack. The article “Applying Fractal Analysis to Short Sets of Heart Rate Variability Data” compared values of α1 computed from long series of measurements (approximately 40,000 heartbeats) with those estimated from the first 300 beats to determine how well the long-term measurement (y) could be predicted the short-term one (x). Following are the data (obtained by digitizing a graph). Short Long 0.54 0.55 1.02 0.79 1.4 0.81 0.88 0.9 1.68 1.05 1.16 1.05 0.82 1.05 0.93 1.07 1.26 1.1 1.18 1.19 0.81 1.19 0.81 1.2 1.28 1.23 1.18 1.23 0.71 1.24 Note: This problem has a reduced data set for ease of performing the calculations required. This differs from the data set given for this problem in the text. Compute the least-squares line for predicting the long-term measurement from the short-term measurement.…
Show theoretically that sin 2 x(secx + cosecx) = (1+ tanx) cosx.tanx , Then confirm orverify using the given value of x = 30
State whether the following statements true or false 1. The type I error and type II error are related. A decrease in the probability of one generally results in an increase in the probability of the other. 2. The size of the critical region, and therefore the probability of committing a type I error, can always be reduced by adjusting the critical value(s). 3. An increase in the sample size n will reduce α and β simultaneously. 4. If the null hypothesis is false, β is a maximum when the true value of a parameter approaches the hypothesized value. The greater the distance between the true value and the hypothesized value, the smaller β will be. 5. The power of a test is the probability of rejecting H0 given that a specific alternative is true.
32 - If the velocity of water flowing through a pipe with a diameter of 134 mm is 1.89 m/s, which of the following is the volumetric flow of water? a) 0.01664 m³/h B) 0.02891 m³/h NS) 0.01895 m³/h D) 0.02665 m³/s TO) 0.02389 m³/s
The accuracy of 61,000 N is: A. 5 B. 4 C. 3 D. 2 E. 1 The precision of 61,000 N: The precision of 610.00 cm is: The precision of 900,100 ft^3: 10.06m+16,000 cm+18.4760m+102,500cm= (470 yard)x(1200ft) =