Assume ip is a pointer to an int. Write a statement that will dynamically allocate an array of 500 integers and store its address in ip, then write a statement that will free the memory allocated in the statement you just wrote.
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Assume ip is a pointer to an int. Write a statement that will dynamically allocate an array of 500 integers and store its address in ip, then write a statement that will free the memory allocated in the statement you just wrote.
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- 1)Answer the question with the correct option A) Which of the following assigns to the pointer p to the address of value? options are given p = value; *p = &value; p = &value; p = &value;1)Answer the question with the correct option A) Which of the following assigns to the pointer p to the address of value? options are given p = value; *p = &value; p = &value; p = &value; B) What is the output of the following code fragment? Options are given below the code: int v1=2, v2=-1, *p1, *p2; p1 = &v1; p2 = &v2; p2 = p1; cout << *p2 << endl; 2 -2 1 -1 C) Which of the following statements correctly prints out the value that is in the memory address that the pointer p is pointing to? cout << int* p; cout << p; cout << *p; cout << &p;// Program 4.6.1 #include <iostream>using namespace std;int main (){int X = 5, Y = 15; int * p1, * p2;p1 = &X; // p1 = address of Xp2 = &Y; // p2 = address of Y*p1 = 10; // value pointed by p1 = 10*p2 = *p1; // value pointed by p2 = value pointed by p1p1 = p2; // p1 = p2 (value of pointer is copied)*p1 = 40; // value pointed by p1 = 20cout << "X is " << X << endl;cout << "Y is " << Y << endl;return 0;} TASK 1. Explain in details what the program does? 2. What is the output
- What is the address of (int) m[i][j] in terms of the base address and COLS? What are potential problems with <code>strcpy()</code> and <code>strcat</code> Why does <code>scanf()</code> take a pointer?// Program 4.4.1#include <iostream>using namespace std;int main (){ int var = 20; // actual variable declaration. int *ip; // pointer variable ip = &var; // store address of var in pointer variable cout << "Value of var variable: "; // print the variable value cout << var << endl<<endl; cout << "Address stored in ip variable: "; // print the address stored in ip pointer variable cout << ip << endl<<endl; cout << "Value of *ip variable: "; // access the value at the address available in pointer cout << *ip << endl; return 0;} TASK 1. Explain in details what the program does? 2. What is the output.In c++ you have a data in a text file, the data consists of a chatacter separated by a comma then an integer also separate md by a comma then another integer Example A,11,1 B,13,2 C,14,4 D,15,7 E,40,1 F,50,1 How will you read and store the data in a vector such that the character will be stored in vector char, and the two integers will be stored in vector x and y respectively.
- Write a short C program that declares and initializes (to any value you like) adouble, an int, and a char. Next declare and initialize a pointer to each of thethree variables. Your program should then print the address of, and value storedin, and the memory size (in bytes) of each of the six variables.Use the “%p” formatting specifier to print addresses in hexadecimal. You shouldsee addresses that look something like this: "0xbfe55918". The initial characters"0x" tell you that hexadecimal notation is being used; the remainder of the digitsgive the address itself. Use proper formatting specifiers for char, int and double.Use the sizeof operator to determine the memory size allocated for each variable.Sample output from your program:The address of char ___ is 0x_______The address of int ___ is 0x_______The address of double ___ is 0x_______The address of char* ___ is 0x_______The address of int* ___ is 0x_______The address of double* ___ is 0x_______The value of char ___ is _______The…Write a C program that uses the following: a main() to read two integer values from the user, val1 and val2, and prints the returned value from swap().a swap() that uses call by reference (takes the addresses into pointers) to swap values, and prints their values after the swap "num1 = # and num2 = #". This function returns the largest of the two values. If these are equal, it returns their sum.Given the declaration below, if array aData[][] was associated to the memory location 1010 (in decimal), what is the value/address (in decimal) equivalent to aData[5] ? double aData[6][4]; Note that sizeof(double) results to 8, meaning 8 bytes.
- Write a short C program that declares and initializes (to any value you like) adouble, an int, and a char. Next declare and initialize a pointer to each ofthe three variables. Your program should then print the address of, and valuestored in, and the memory size (in bytes) of each of the six variables.Use the “0x%x” formatting specifier to print addresses in hexadecimal. Youshould see addresses that look something like this: "0xbfe55918". The initialcharacters "0x" tell you that hexadecimal notation is being used; the remainderof the digits give the address itself.Use the sizeof operator to determine the memory size allocated for eachvariable.*/What is the correct way to assign the pointer p to the address of x?. Single choice. p = %x; p = &x; &p = *x; *p = &x;Write a block of code that uses a dynamic allocated array named Array to (1) Load ten integers from the user into the memory, (2) Find the number of negative integers in the array, and (3) Print a message with the number of negatives. Whenever no numbers are negative print an additional message "No negatives!" (Assume all libraries are included)