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Assume that a procedure yields a binomial distribution with n = 2 trials and a probability of success of p = 0.05. Use a binomial probability table to find the probability that the number of successes x is exactly 1. Click on the icon to view the binomial probabilities table. P(1) = (Round to three decimal places as needed.)

Assume that a procedure yields a binomial distribution with n = 2 trials and a probability of success of p = 0.05. Use a binomial probability table to find the probability that the number of successes x is exactly 1. Click on the icon to view the binomial probabilities table. P(1) = (Round to three decimal places as needed.)

College Algebra
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.3: Binomial Probability
Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...
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Binomial Probabilities Table Binomial Probabilities .01 .05 .10 .20 .30 .40 .50 60 .70 80 .90 .95 .99 2 .980 .902 .810 .640 .490 .360 .250 .160 090 040 010 002 0+ 2 1 020 .095 .180 .320 .420 .480 500 A80 420 .180 095 .020 1 2 0+ .002 .010 .040 .090 .160 .250 360 490 640 810 902 .980 2 3 .970 .857 .729 .512 .343 .216 .125 064 027 008 001 0+ 0+ 3 1 029 .135 .243 .384 .441 .432 .375 208 .189 095 027 007 0+ 2 0+ .007 .027 .096 .189 .288 .375 432 441 384 243 .135 .029 2 3 0+ 0+ .001 .008 .027 .064 .125 216 343 512 .729 857 .970 3 .961 .815 .656 410 .240 .130 .062 026 008 002 0+ 0+ 0+ 1 039 .171 .292 410 .412 .346 .250 .154 076 026 004 0+ 0+ 1 2 001 .014 .049 .154 .265 .346 .375 346 265 .154 049 014 .001 2 3 0+ 0+ .004 .026 .076 .154 .250 346 412 410 292 .171 .039 3 4 0+ 0+ 0+ .002 .008 .026 .062 .130 240 410 656 815 .961 4. .951 .774 .590 .328 .168 .078 .031 010 002 0+ 0+ 0+ 0+ 5 1 048 .204 .328 410 .360 .259 .156 077 028 006 0+ 0+ 0+ 2 001 .021 .073 .205 .309 .346 .312 230 .132 051 008 001 0+ 3 0+ .001 .008 .051 .132 .230 .312 346 309 205 073 021 .001 3 4 0+ 0+ 0+ .006 .028 .077 .156 259 360 410 328 204 .048 5 0+ 0+ 0+ 0+ .002 .010 .031 078 .168 328 590 .774 .951 5 .941 .735 .531 .262 .118 .047 .016 004 001 0+ 0+ 0+ 1 057 .232 .354 .393 .303 .187 .094 037 010 002 0+ 0+ 0+ 2 001 .031 .098 246 .324 .311 .234 .138 060 015 001 0+ 0+ 3 0+ .002 .015 .082 .185 .276 .312 276 .185 082 015 002 0+ 3 4 0+ 0+ .001 .015 .060 .138 .234 311 324 246 098 031 .001 4 Print Done
Transcribed Image Text:Binomial Probabilities Table Binomial Probabilities .01 .05 .10 .20 .30 .40 .50 60 .70 80 .90 .95 .99 2 .980 .902 .810 .640 .490 .360 .250 .160 090 040 010 002 0+ 2 1 020 .095 .180 .320 .420 .480 500 A80 420 .180 095 .020 1 2 0+ .002 .010 .040 .090 .160 .250 360 490 640 810 902 .980 2 3 .970 .857 .729 .512 .343 .216 .125 064 027 008 001 0+ 0+ 3 1 029 .135 .243 .384 .441 .432 .375 208 .189 095 027 007 0+ 2 0+ .007 .027 .096 .189 .288 .375 432 441 384 243 .135 .029 2 3 0+ 0+ .001 .008 .027 .064 .125 216 343 512 .729 857 .970 3 .961 .815 .656 410 .240 .130 .062 026 008 002 0+ 0+ 0+ 1 039 .171 .292 410 .412 .346 .250 .154 076 026 004 0+ 0+ 1 2 001 .014 .049 .154 .265 .346 .375 346 265 .154 049 014 .001 2 3 0+ 0+ .004 .026 .076 .154 .250 346 412 410 292 .171 .039 3 4 0+ 0+ 0+ .002 .008 .026 .062 .130 240 410 656 815 .961 4. .951 .774 .590 .328 .168 .078 .031 010 002 0+ 0+ 0+ 0+ 5 1 048 .204 .328 410 .360 .259 .156 077 028 006 0+ 0+ 0+ 2 001 .021 .073 .205 .309 .346 .312 230 .132 051 008 001 0+ 3 0+ .001 .008 .051 .132 .230 .312 346 309 205 073 021 .001 3 4 0+ 0+ 0+ .006 .028 .077 .156 259 360 410 328 204 .048 5 0+ 0+ 0+ 0+ .002 .010 .031 078 .168 328 590 .774 .951 5 .941 .735 .531 .262 .118 .047 .016 004 001 0+ 0+ 0+ 1 057 .232 .354 .393 .303 .187 .094 037 010 002 0+ 0+ 0+ 2 001 .031 .098 246 .324 .311 .234 .138 060 015 001 0+ 0+ 3 0+ .002 .015 .082 .185 .276 .312 276 .185 082 015 002 0+ 3 4 0+ 0+ .001 .015 .060 .138 .234 311 324 246 098 031 .001 4 Print Done
Assume that procedure yields a binomial distribution with n =2 trials and a probability of success of p = 0.05. Use a binomial probability table to find the probability that the number of successes x is exactly 1. E Click on the icon to view the binomial probabilities table. P(1) = (Round to three decimal places as needed.)
Transcribed Image Text:Assume that procedure yields a binomial distribution with n =2 trials and a probability of success of p = 0.05. Use a binomial probability table to find the probability that the number of successes x is exactly 1. E Click on the icon to view the binomial probabilities table. P(1) = (Round to three decimal places as needed.)
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